f(x) = x5 ln(x) e-² 1+x² f(1.05)= 0.009834065665 f'(1.05)= 0.2083153204 f" (1.05) = 0.4190655947 Find the value, absolute error and relative error of the f'(1.05) and f"(1.05) function using derivative calculation with forward differences.

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