f(x) = x² + x - 12 g(x) = x - 3

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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---

In this lesson, we will explore how to find the quotient of two functions and determine the domain of the resulting function.

Given the functions:

\[ f(x) = x^2 + x - 12 \]
\[ g(x) = x - 3 \]

**Task:**

1. **Find** \(\left(\frac{f}{g}\right)(x)\).

2. **Determine the domain of** \(\left(\frac{f}{g}\right)(x)\).

\[ \left(\frac{f}{g}\right)(x) = \boxed{\phantom{\rule{4cm}{0.4pt}}} \]

\[ \text{The domain of} \left(\frac{f}{g}\right)(x) \text{ is } x \ne \boxed{\phantom{\rule{2cm}{0.4pt}}} \]

---

**Explanation:**

To find \(\left(\frac{f}{g}\right)(x)\), we divide \( f(x) \) by \( g(x) \):

\[ \left(\frac{f}{g}\right)(x) = \frac{f(x)}{g(x)} = \frac{x^2 + x - 12}{x - 3} \]

Next, we factor the numerator \( x^2 + x - 12 \):

\[ x^2 + x - 12 = (x - 3)(x + 4) \]

So,

\[ \left(\frac{f}{g}\right)(x) = \frac{(x - 3)(x + 4)}{x - 3} \]

When simplifying, we must consider \( x \ne 3 \) (to avoid division by zero):

\[ \left(\frac{f}{g}\right)(x) = x + 4, \quad \text{for } x \ne 3 \]

Thus, the simplified function is:

\[ \left(\frac{f}{g}\right)(x) = x + 4 \]

**The domain of** \(\left(\frac{f}{g}\right)(x)\) **is** \( x \ne 3 \).

\[ \boxed{x + 4} \]

\[ \text{The domain of} \left(\frac{f}{g}\right)(
Transcribed Image Text:Certainly! Here is the transcribed content for the educational website: --- In this lesson, we will explore how to find the quotient of two functions and determine the domain of the resulting function. Given the functions: \[ f(x) = x^2 + x - 12 \] \[ g(x) = x - 3 \] **Task:** 1. **Find** \(\left(\frac{f}{g}\right)(x)\). 2. **Determine the domain of** \(\left(\frac{f}{g}\right)(x)\). \[ \left(\frac{f}{g}\right)(x) = \boxed{\phantom{\rule{4cm}{0.4pt}}} \] \[ \text{The domain of} \left(\frac{f}{g}\right)(x) \text{ is } x \ne \boxed{\phantom{\rule{2cm}{0.4pt}}} \] --- **Explanation:** To find \(\left(\frac{f}{g}\right)(x)\), we divide \( f(x) \) by \( g(x) \): \[ \left(\frac{f}{g}\right)(x) = \frac{f(x)}{g(x)} = \frac{x^2 + x - 12}{x - 3} \] Next, we factor the numerator \( x^2 + x - 12 \): \[ x^2 + x - 12 = (x - 3)(x + 4) \] So, \[ \left(\frac{f}{g}\right)(x) = \frac{(x - 3)(x + 4)}{x - 3} \] When simplifying, we must consider \( x \ne 3 \) (to avoid division by zero): \[ \left(\frac{f}{g}\right)(x) = x + 4, \quad \text{for } x \ne 3 \] Thus, the simplified function is: \[ \left(\frac{f}{g}\right)(x) = x + 4 \] **The domain of** \(\left(\frac{f}{g}\right)(x)\) **is** \( x \ne 3 \). \[ \boxed{x + 4} \] \[ \text{The domain of} \left(\frac{f}{g}\right)(
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