Only qno1 solve . See sample I need like this. Note: bisection method ok. 11F: X 3-4x-974-001X 51X-8900317:10.000이명SXX4 03.55 296 369625ㅋ 905425552.53993 1253.125380578125 369625QNAS 099343758774335 19.6953/32148948 2.695313 ㅋㅋㅋㅋㅋㅋ69 3-4955131989410 2,705099아케이144111 17050747. 909902xới 706528 là gì trên 72705079d7099622375213.30033.375-3395-3.3953375-6.180392-04339239--0-200539-0.06.09-0.1086029-0.02.0990요 ㅋ 349399017598799931419933140 948930:504930.1500500.15100010.1614260.019059-3.99998.7543799.0175780 500893-0.20057901500900.0260290.06/826O.OVABST0 004097 f(x)= x² - 4x-15XR = 87XL = 0.01f(x)=x² +15x-98X₂₁:0XR = 10Tot = 0.01L

Given f(x)=x3−4x−15,XL=0,xR=8 Now f(0)=03−4×0−15=−15and f(8)=83−4×8−15=465So root lies in [0,8] .To…

Answered: f(x)= x² - 4x-15 X₁ = 0 X₂ = 8 7L=0.01…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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f(x)= x² - 4x-15 X₁ = 0 X₂ = 8 7L=0.01 f(x)= x² +15x-98 X₁₂:0 XR = 10 Tot = 0.01