f(x) = x° + 3x³ + 2x 2 - f'(x) = f'"(x) = f'(x) = f(4) (æ) =

Q: Find y=f(x), if f''(x)=3x^2, f'(0)=-7 and f(0)=2.

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Q: Find f'(0) for the function f (x) = 3.xe 5x %3D Answer:

A: use the formula for the derivative  d ( u v ) = u dv + v du  ddxeax=aeax,ddxax=a

Q: If ƒ(x) = 4x² – 5eª, find: ƒ'(x) = f'(1) = ƒ''(x) = f''(1) =

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Q: find f'(x) and f"(x). : If f(x) x² +3 f'(x) = f"(x) =

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Q: If f(x) = 2 sec (8x), find f'(x). Find f'(3).

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Q: Find f'(a) for f'(a) = f(x): = -9 √2 - 4x

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Q: Find  f'(a)

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Q: Find f'(x) and f'(c). Function f(x) = (x³ + 4x)(7x² + 5x − 6) f'(x) = - f'(c) = = Value of c 0 = 5

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Q: If f(x) = 3x? – 2e", find: f'(x) = = (x),.

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Q: Find f'(x). f(x)=9e-7x f'(x) =

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Q: Find  f '(a). f(x) =    1 − 4x

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Q: Find f'(x). f(x) = − 5 In x + 11x² - 10 f'(x) =

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Q: Find f'(x). f(x) = (x+9)¯ -2 f'(x) = ☐

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Q: Find f'(x) for f(x) = e2xsec-1(2x)

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Q: Find f'(x) for f(x) = 8x³. f'(x) =

A: To find .

Q: Find f'(x) and f'(c). Function Value of c f(x) = (x³ + 2x)(5x³ + 5x – 4) c = 0 f'(x) = f'(c) =

A: Given fx=x5+2x5x5+5x-4c=0

Q: Find f'(2²) if (f(x²)] = x4.

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Q: Find f'(x), f''(x), and f (x) for the following function. f(x) = 6x +8x2 + 3x f'(x) = f'"(x) = f3)…

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Q: Find f'(x), f'"(x), and f()(x) for the following function. f(x) = 6e* f'(x)= O f'"(x) =D

A: We have to find derivatives of the given function.

Q: If f'(x) = 3x2. 2 and X f (1) = 0, find f (x)

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Q: Find y=f(x) if f''(x)=4x^2, f'(0)=3, and f(0)=2.

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Q: f(x) = (x³ + 2x + 7)4 f' (æ) = f' (5) =

A: Consider the given function: fx=x3+2x+74 Differentiate the function using chain rule which is given…

Q: B. f"(x)=8x³ +5, ƒ(1)=0, ƒ'(1)=8

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Q: Find f. f ''(x) = −2 + 12x − 12x2,    f(0) = 9,    f '(0) = 18   f(x) =

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Q: f"(x) = 5x – 5 %3D - and f' (-3) = 5 and f(-3) = 5. %3D Find f'(x) = and find f(4) = %3D

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Q: Find f'(a). ƒ'(a) = f(x) = V 2 - 2x

A: Given query is to find indicated derivative.

Q: f(x)=150x/-25x-10 f'(x)=?

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Q: Find f'(a). f(x) = 3x2 4x + 2 f'(a) =

A: Let a function gx to find the value of g'c, First differentiate the function with respect to x, and…

Q: Find g’(2) when g(x)=f(x-x^2) and f’(-2)=1/3.

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