f(x) = x° + 3x³ + 2x 2 - f'(x) = f'"(x) = f'(x) = f(4) (æ) =

Q: Find f'(x). f(x) = 7e f'(x) = 3x 3

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Q: Find y=f(x), if f''(x)=3x^2, f'(0)=-7 and f(0)=2.

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Q: Find f'(0) for the function f (x) = 3.xe 5x %3D Answer:

A: use the formula for the derivative  d ( u v ) = u dv + v du  ddxeax=aeax,ddxax=a

Q: find f'(x) and f"(x). : If f(x) x² +3 f'(x) = f"(x) =

A:

Q: Find f'(x). f(x) = 2 In (2+7x2)

A: Taking derivative with respect to x,   Take the constant 2 out of the brackets,

Q: If f(x) = 2 sec (8x), find f'(x). Find f'(3).

A:

Q: Find f'(x) and f'(c). Function f(x) = (x³ + 4x)(7x² + 5x − 6) f'(x) = - f'(c) = = Value of c 0 = 5

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Q: If f(x) = 3x? – 2e", find: f'(x) = = (x),.

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Q: Find f'(x). f(x)=9e-7x f'(x) =

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Q: Find  f '(a). f(x) =    1 − 4x

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Q: Find f'(x). f(x) = − 5 In x + 11x² - 10 f'(x) =

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Q: f"(x) = 2x + 2 and f'(-1) = –3 and f(-1) = 0. Find f'(x) = %D and find f(3) = ...

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Q: Find f'(x). f(x)=(7x+4)(9x-3) f'(x)= (Type an exact answer.)

A: Given, .Rules of derivative:

Q: Find f'(x). f(x) = (x+9)¯ -2 f'(x) = ☐

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Q: Find f'(x) for f(x) = 8x³. f'(x) =

A: To find .

Q: Find f'(x). f(x) = f'(x) = 9x - 1 4x + 3

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Q: If f(x) = 7x² f'(2) = f''(x) = f''(2) = 8e, find:

A: The given function is fx=7x2-8ex

Q: Find f. f ''(x) = −2 + 36x − 12x2,    f(0) = 5,    f '(0) = 18

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Q: Find f. f ''(x) = −2 + 12x − 12x2,    f(0) = 9,    f '(0) = 18   f(x) =

A: