fx (X) = 0.06x+0.05 X = 0, 1.5, 2, 4, 5 Since it is a discrete pdf, calculations will accomplished through summation. The E[X] = 3.46. Determine Var(X). Round your answer to two decimal places
fx (X) = 0.06x+0.05 X = 0, 1.5, 2, 4, 5 Since it is a discrete pdf, calculations will accomplished through summation. The E[X] = 3.46. Determine Var(X). Round your answer to two decimal places
fx (X) = 0.06x+0.05 X = 0, 1.5, 2, 4, 5 Since it is a discrete pdf, calculations will accomplished through summation. The E[X] = 3.46. Determine Var(X). Round your answer to two decimal places
Since it is a discrete pdf, calculations will accomplished through summation.
The E[X] = 3.46. Determine Var(X).
Transcribed Image Text:Consider the following pdf:
fr (x) = 0.06x +0.05
X = 0, 1.5, 2, 4, 5
Since it is a discrete pdf, calculations will accomplished through summation.
The E[X] = 3.46. Determine Var(X).
Round your answer to two decimal places
Definition Definition Probability of occurrence of a continuous random variable within a specified range. When the value of a random variable, Y, is evaluated at a point Y=y, then the probability distribution function gives the probability that Y will take a value less than or equal to y. The probability distribution function formula for random Variable Y following the normal distribution is: F(y) = P (Y ≤ y) The value of probability distribution function for random variable lies between 0 and 1.
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![Consider the following pdf:
fr (x) = 0.06x +0.05
X = 0, 1.5, 2, 4, 5
Since it is a discrete pdf, calculations will accomplished through summation.
The E[X] = 3.46. Determine Var(X).
Round your answer to two decimal places](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fea1167bf-2867-4249-8be3-5eefd73abe81%2Fda4fc1f5-40f7-41bb-97ce-2cd0537f22c8%2Fs0eeb8i_processed.png&w=3840&q=75)
