f(x) = Vx3 + 9

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
icon
Related questions
icon
Concept explainers
Question

Find a  domain on which f is one-to-one and a formula for the inverse off restricted to this domain. Sketch the graphs off and f- 1.

f(x) = Vx3 + 9
Transcribed Image Text:f(x) = Vx3 + 9
Expert Solution
Step 1: Given:

f left parenthesis x right parenthesis equals square root of x cubed plus 9 end root

To find: domain on which f is one-to-one and a formula for the inverse of f restricted to this domain. Also sketch the graphs of f and f to the power of negative 1 end exponent.

Step 2: Finding domain of f.

Since the square root function is defined on nonnegative values only.

table attributes columnalign right center left columnspacing 0px end attributes row cell x cubed plus 9 end cell greater or equal than 0 row cell x cubed end cell greater or equal than cell negative 9 end cell row x greater or equal than cell open parentheses negative 9 close parentheses to the power of 1 third end exponent end cell end table

Domain: left square bracket open parentheses negative 9 close parentheses to the power of 1 third end exponent comma infinity right parenthesis


Step 3: Finding inverse of f

table attributes columnalign right center left columnspacing 0px end attributes row cell Let space y end cell equals cell square root of x cubed plus 9 end root end cell row cell y squared end cell equals cell x cubed plus 9 end cell row cell x cubed end cell equals cell y squared minus 9 end cell row x equals cell open parentheses y squared minus 9 close parentheses to the power of 1 third end exponent end cell end table

Replace x with y.

table attributes columnalign right center left columnspacing 0px end attributes row cell f to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell open parentheses x squared minus 9 close parentheses to the power of 1 third end exponent end cell end table


steps

Step by step

Solved in 6 steps with 25 images

Blurred answer
Knowledge Booster
Application of Differentiation
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, advanced-math and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Basic Technical Mathematics
Basic Technical Mathematics
Advanced Math
ISBN:
9780134437705
Author:
Washington
Publisher:
PEARSON
Topology
Topology
Advanced Math
ISBN:
9780134689517
Author:
Munkres, James R.
Publisher:
Pearson,