f(x) = Vx – 3. Use interval notation to indicate where f is continuous. Domain of continuity:

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Use **interval notation** to indicate where \( f \) is continuous.

**Function Definition:**

\[ f(x) = \sqrt{x - 3} \]

**Task:**

Determine the domain of continuity for the function \( f(x) \). Enter your answer in the space provided.

**Explanation of the Mathematical Concept:**

The function \( f(x) = \sqrt{x - 3} \) involves a square root, which is only defined for non-negative numbers. This means that the expression inside the square root, \( x - 3 \), must be greater than or equal to zero for the function to be continuous. 

Solve the inequality:

\[ x - 3 \geq 0 \]

\[ x \geq 3 \]

Thus, the function \( f \) is continuous for all \( x \) in the interval \([3, \infty)\).

**Domain of Continuity:**

Enter the domain of continuity below:

\[ \text{Domain of continuity: } [3, \infty) \]
Transcribed Image Text:**Problem Statement:** Use **interval notation** to indicate where \( f \) is continuous. **Function Definition:** \[ f(x) = \sqrt{x - 3} \] **Task:** Determine the domain of continuity for the function \( f(x) \). Enter your answer in the space provided. **Explanation of the Mathematical Concept:** The function \( f(x) = \sqrt{x - 3} \) involves a square root, which is only defined for non-negative numbers. This means that the expression inside the square root, \( x - 3 \), must be greater than or equal to zero for the function to be continuous. Solve the inequality: \[ x - 3 \geq 0 \] \[ x \geq 3 \] Thus, the function \( f \) is continuous for all \( x \) in the interval \([3, \infty)\). **Domain of Continuity:** Enter the domain of continuity below: \[ \text{Domain of continuity: } [3, \infty) \]
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