What is the total force on the pipe bend (Fr)? Assume no losses F = P,A,cos0, – P2A,cos0, – pQ(V,cos0 , – V,cos0 ; )Fy = P,Aqsin0, – P2A,sin0, – pQ(V„sin0 , – V,sin0 , )F.12sin(90°) = 1, sin(0°) = 0cos(90°) = 0, cos(0°) = 1F1 = 315 NF2 = 323 NQ = 1 m³ s-1D = 1 mp =1000 kg m-2

Answered: Image /qna-images/answer/73a97469-d7ed-4bf3-b3ab-e8a4616676b0.jpg

Answered: Fx = P,A,cos0, – P2A,cos0, – pQ(V,cos0…

Fx = P,A,cos0, – P2A,cos0, – pQ(V,cos0 , – V,cos0 ; ) F, = P,A,sin0, – P2A2sin0, – pQ(V2sin0 , – V;sin0 ; ) %3D - - - - - 1

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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