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f(x) = ax² + bx + 3, 1 2bx + 13a f(-2)=1 six < −2 six = -2 six >−2

f(x) = ax² + bx + 3, 1 2bx + 13a f(-2)=1 six < −2 six = -2 six >−2

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
f(x) = ax² + bx + 3, 1 2bx + 13a f(-2)=1 ) lim f(x) X-)) six < −2 six = -2 six >−2 X = lim f(x)
Transcribed Image Text:f(x) = ax² + bx + 3, 1 2bx + 13a f(-2)=1 ) lim f(x) X-)) six < −2 six = -2 six >−2 X = lim f(x)
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