f(x) and (f'(x))² into the surface area equation above to find b Surface Area = Lº 2π. = a 5 5 2π f(x)√1+ (f'(x))² dx 2π√3x 61+ 3 4x 8 - 3(3x-6) dx = L² 2m 2π 3x-6+ dx 4x 8 = 1 5 T√12x-15 dx. FEEDBACK CONTINUE
f(x) and (f'(x))² into the surface area equation above to find b Surface Area = Lº 2π. = a 5 5 2π f(x)√1+ (f'(x))² dx 2π√3x 61+ 3 4x 8 - 3(3x-6) dx = L² 2m 2π 3x-6+ dx 4x 8 = 1 5 T√12x-15 dx. FEEDBACK CONTINUE
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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How was the 2 used from 2pie. How is it determined the 2 is needed
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VA
F
f(x) and (f'(x))² into the surface area equation above to find
Surface Area =
Sº
= 2 TJ
a
5
2f(x)√1+ (f'(x)) dx
= 2π
2π√√3x 61+
3
4x - 8
dx
=
5
2π 3x 6+
3(3x-6)
dx
4x - 8
5
-L
T√12x-15 dx.
FEEDBACK
CONTINUE
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