f(x) * a = 49 (2n – 1)! 2". 72n + 1 + (x – 49)" n = 1 1 ㅇ윽+>m.72n+ 1.n! 1 (x - 49)" n = 0 1 1:3.5. .... (2n – 1) -E(-1)^- (x – 49)" 2n. 72n - 1. n! n= 1 1 -E(-1)^ + 1 (x - 49)" + 2". 72n. n! n = 1 S(-1)^3. 5. .... (2n – 1) 2". 72n + 1.n! 1 (x - 49)" n = 1
f(x) * a = 49 (2n – 1)! 2". 72n + 1 + (x – 49)" n = 1 1 ㅇ윽+>m.72n+ 1.n! 1 (x - 49)" n = 0 1 1:3.5. .... (2n – 1) -E(-1)^- (x – 49)" 2n. 72n - 1. n! n= 1 1 -E(-1)^ + 1 (x - 49)" + 2". 72n. n! n = 1 S(-1)^3. 5. .... (2n – 1) 2". 72n + 1.n! 1 (x - 49)" n = 1
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that R,(x) - 0.]
1
f(x) =
a = 49
(2n – 1)!
(-1)"-
2n.72n +1
(х - 49)л
n = 1
2n. 72n + 1. n!
(x - 49)"
= 0
(-1)- 3. 5..... (2n - 1)
2". 72n - 1. n!
(x - 49)n
n = 1
1
(-1)n + 1
(x - 49)"
2n. 72n. n!
n = 1
(-1)1:3. 5..... (2n - 1)
2n . 72n + 1 . n!
(x - 49)"](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F966b9752-0e6e-47d7-af8f-ce4bbf704a72%2F039b3fb0-3278-4e70-a4da-088f85d8efc9%2Fcts9ih9_processed.png&w=3840&q=75)
Transcribed Image Text:Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that R,(x) - 0.]
1
f(x) =
a = 49
(2n – 1)!
(-1)"-
2n.72n +1
(х - 49)л
n = 1
2n. 72n + 1. n!
(x - 49)"
= 0
(-1)- 3. 5..... (2n - 1)
2". 72n - 1. n!
(x - 49)n
n = 1
1
(-1)n + 1
(x - 49)"
2n. 72n. n!
n = 1
(-1)1:3. 5..... (2n - 1)
2n . 72n + 1 . n!
(x - 49)"
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