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(f'(x))² = 4 (52 – 8) - 25 = 20x 32 (f'(x))2 into the surface area equation above to find Surface Area = b S" (2m a 4 2π f(x)√/1+ (f'(x))²) dx 8. 25 = 1² (2√5-8√/1 + x = 32) dr = S 2 -1 (2-√5x-7) dr. 2 4 20x -

(f'(x))² = 4 (52 – 8) - 25 = 20x 32 (f'(x))2 into the surface area equation above to find Surface Area = b S" (2m a 4 2π f(x)√/1+ (f'(x))²) dx 8. 25 = 1² (2√5-8√/1 + x = 32) dr = S 2 -1 (2-√5x-7) dr. 2 4 20x -

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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 how do you combine the two radicals?  the answer is given I just need to know how you combine the two radicals to get to pi to the square root of 5X -7/4
(f'(x))² = 4(52 – 8) - 25 20x32 d (f'(x))2 into the surface area equation above to find Surface Area = b S" (2m ୮" a 4 2π f(x)√1+ (f'(x))²) dx dx = (2√38-8√1 + 702537) dr earch 4 = 2π/5x 7) dx. Activity Details IA O FEEDBA
Transcribed Image Text:(f'(x))² = 4(52 – 8) - 25 20x32 d (f'(x))2 into the surface area equation above to find Surface Area = b S" (2m ୮" a 4 2π f(x)√1+ (f'(x))²) dx dx = (2√38-8√1 + 702537) dr earch 4 = 2π/5x 7) dx. Activity Details IA O FEEDBA
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