FW m Transmittance % Solvent: CDC13 4830 4000 2.10 1000 3000 CsH₂O2 2008 1983 2000 Wavenumber 1500 cm-1 3.0 1.01 2.5 1000 1000 300 500 3.15 The number underneath each peak in 'H NMR spectrum represents relative integration value.
FW m Transmittance % Solvent: CDC13 4830 4000 2.10 1000 3000 CsH₂O2 2008 1983 2000 Wavenumber 1500 cm-1 3.0 1.01 2.5 1000 1000 300 500 3.15 The number underneath each peak in 'H NMR spectrum represents relative integration value.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
The IR, and 1H NMR spectra of a compound with formula C5H6O2 are shown below. Determine the structure of the compound. You must fill all the parts to this question in the given spaces.
![FAY
Solvent: CDC13
D
4830
4000
2.10
Solution of problem # 2:
Degree of unsaturation:
IR interpretation:
3000
3000
Peak A (4.25 ppm)
4,0
C5H602
POOR
1983
2000 Wavenumber 1500
cm 1
3.0
1.01
2.5
The number underneath each peak in 'H NMR spectrum represents relative integration value.
Peak B (2.90 ppm)
1000
1000
800
500
'H NMR interpretation (I want a picture of the fragment that you can determine from the shift and
splitting):
Structure of unknown compound
3.15
Peak C (1.35 ppm)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F70e1f315-55f6-4253-9395-66ce7a67cf3a%2F8aadfa19-e507-42ed-a28b-83f1db53f353%2Fx263rdp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:FAY
Solvent: CDC13
D
4830
4000
2.10
Solution of problem # 2:
Degree of unsaturation:
IR interpretation:
3000
3000
Peak A (4.25 ppm)
4,0
C5H602
POOR
1983
2000 Wavenumber 1500
cm 1
3.0
1.01
2.5
The number underneath each peak in 'H NMR spectrum represents relative integration value.
Peak B (2.90 ppm)
1000
1000
800
500
'H NMR interpretation (I want a picture of the fragment that you can determine from the shift and
splitting):
Structure of unknown compound
3.15
Peak C (1.35 ppm)
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