1.280.85, or 85%1.440.90, or 90%1.6450.95, or 95%1.960.98, or 98%2.330.99, or 99%2.58Z0.99= 2.58Furthermore, you will need to estimate E, the maximal margin of error which can be approximatedE= zApproximate the maximal margin of error, E, by using z from above, the given population standarddeviation, and the sample size, n.Recall that n = 45 and3-7.50. (Round your answer to two decimal places.)70.997.50= \2,58V45I3D

Name: 1.280.85, or 85%1.440.90, or 90%1.6450.95, or 95%1.960.98, or 98%2.33
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Description: 1.280.85, or 85%1.440.90, or 90%1.6450.95, or 95%1.960.98, or 98%2.330.99, or 99%2.58Z0.99= 2.58Furthermore, you will need to estimate E, the maximal margin of error which can be approximatedE= zApproximate the maximal margin of error, E, by using z

We have given that, Sample size n=45, and σ=7.5. Margin of error (E) formula at 99% confidence…

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Furthermore, you will need to estimate E, the maximal margin of error which can be approximatec E = Z from above, the given population standard Approximate the maximal margin of error, E, by using z deviation, and the sample size, n. Recall thatn = 45 and o = 7.50. (Round your answer to two decimal places.) E = Z0.99 7.50 2.58 V 45

Furthermore, you will need to estimate E, the maximal margin of error which can be approximatec E = Z from above, the given population standard Approximate the maximal margin of error, E, by using z deviation, and the sample size, n. Recall thatn = 45 and o = 7.50. (Round your answer to two decimal places.) E = Z0.99 7.50 2.58 V 45

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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