FUNDAMENTALS OF SURVEYING A field is in the shape of regular octagon. The direction of the bounding sides were surveyed with an assumed meridian 8deg. to the right of the true north meridian. As surveyed with the given assumed meridian, the bearing of one side (Side 1-2) is N 53deg 20min W. Solve for the true bearing, true north azimuth, and true south azimuth of all the sides.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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FUNDAMENTALS OF SURVEYING

A field is in the shape of regular octagon. The direction of the bounding sides were surveyed with an assumed meridian 8deg. to the right of the true north meridian. As surveyed with the given assumed meridian, the bearing of one side (Side 1-2) is N 53deg 20min W.

Solve for the true bearing, true north azimuth, and true south azimuth of all the sides.

*NOTE*

-Draw a diagram in every line or pair.

- Show your proper solutions ( write it properly please, so that I can understand quickly.)

- I provided a sample problem so that you will know how to solve it just like my instructor's solutions. Please make it simple. 

IT'S THE THIRD TIME I ASKED THIS QUESTION IN HERE SO PLEASE, ANSWER IT CORRECTLY HUHUHU THANK YOU!

Sample Problen Ne 1:
A fidd is
of the bounding sides ware svricyed w an assumed moridian
☺ t the right of the true north meridian. A survgied w/ an
assumed meridian; the beaning f one side AB is N J8° 20' w.
Cal cu loste
AE.
Soufrin:
in the form
of regular pentagon. The dircction
the frue bearng BC,
twa Bzimuth CD
and truc bearing
TH MN
1
33 20`-5°
I Interiror
Angles =(2n -4) x go
log'
= 540
Interior
Angles of c 540' = 1o¢
every
W
poinp
Transcribed Image Text:Sample Problen Ne 1: A fidd is of the bounding sides ware svricyed w an assumed moridian ☺ t the right of the true north meridian. A survgied w/ an assumed meridian; the beaning f one side AB is N J8° 20' w. Cal cu loste AE. Soufrin: in the form of regular pentagon. The dircction the frue bearng BC, twa Bzimuth CD and truc bearing TH MN 1 33 20`-5° I Interiror Angles =(2n -4) x go log' = 540 Interior Angles of c 540' = 1o¢ every W poinp
True.
る,-25 20
Twe
Branina
Azimuthin
Nz8 20 W 151´ 40'
N43 4'E 23' 4'
SGA 20' E 215" 40
Line
18u -0,= 180~23°20
AB
180 + Oz
= 180'+ 4340'
B C
CD
DE S74' WN 7 40'
EA S F540'w177° 40'
TN
3.
ATS
Nor s
Os = 180'-(198 - r)
ess S70' 48 \メ
二
Azímuthe o a 360°
Fam TN / TI
TN/
Oz =N43°40' E
|ogʻ - Bs = G
Os= 108° -Pz <118= 48 40'
A3 =S GA' 20' E
108" - 79°46' 28' 21
28' 2s
ニ
*4> 180° - 108°- (4'20
o4=57°44'W
This slide left blank for whiteboard
Transcribed Image Text:True. る,-25 20 Twe Branina Azimuthin Nz8 20 W 151´ 40' N43 4'E 23' 4' SGA 20' E 215" 40 Line 18u -0,= 180~23°20 AB 180 + Oz = 180'+ 4340' B C CD DE S74' WN 7 40' EA S F540'w177° 40' TN 3. ATS Nor s Os = 180'-(198 - r) ess S70' 48 \メ 二 Azímuthe o a 360° Fam TN / TI TN/ Oz =N43°40' E |ogʻ - Bs = G Os= 108° -Pz <118= 48 40' A3 =S GA' 20' E 108" - 79°46' 28' 21 28' 2s ニ *4> 180° - 108°- (4'20 o4=57°44'W This slide left blank for whiteboard
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