ft., then F2 = 12 x 2 kips = 24 kips (an unrealistic load, but just for the sake of argument, go with it). Notice that the roof is a kind of "saltbox" style. There's a 500 lb. snow load acting perpendicular to the longer slope. The steeper slope has no snow load as we assume that it'll all slide off. Replace this loading system with an equivalent force and couple moment acting at point O, the midpoint of the building's base. F₁ F₂ 500 LB. 20' O 10' 10 10' h h
ft., then F2 = 12 x 2 kips = 24 kips (an unrealistic load, but just for the sake of argument, go with it). Notice that the roof is a kind of "saltbox" style. There's a 500 lb. snow load acting perpendicular to the longer slope. The steeper slope has no snow load as we assume that it'll all slide off. Replace this loading system with an equivalent force and couple moment acting at point O, the midpoint of the building's base. F₁ F₂ 500 LB. 20' O 10' 10 10' h h
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![Pretend you're designing a 2 story building. See the drawing below. You
decide how tall to make each of the two floors (i.e. decide on the value of
h). Let's just say that there are horizontal forces F₁ and F2 and each has a
magnitude equal to its height off the ground times 2 kips. These may be a
combination of earthquake and wind forces. For example, if you let h = 6
ft., then F₂ = 12 x 2 kips = 24 kips (an unrealistic load, but just for the
sake of argument, go with it). Notice that the roof is a kind of "saltbox"
style. There's a 500 lb. snow load acting perpendicular to the longer
slope. The steeper slope has no snow load as we assume that it'll all slide
off. Replace this loading system with an equivalent force and couple
moment acting at point O, the midpoint of the building's base.
F₁
F₂
500
LB.
20'
O
*
10'
*
10'
*
10'
h
h](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F415782a2-fc6e-4671-a73e-3a26a66806a4%2F76ef920e-97db-4d95-a84f-e049194e45ea%2F2mu39zk_processed.png&w=3840&q=75)
Transcribed Image Text:Pretend you're designing a 2 story building. See the drawing below. You
decide how tall to make each of the two floors (i.e. decide on the value of
h). Let's just say that there are horizontal forces F₁ and F2 and each has a
magnitude equal to its height off the ground times 2 kips. These may be a
combination of earthquake and wind forces. For example, if you let h = 6
ft., then F₂ = 12 x 2 kips = 24 kips (an unrealistic load, but just for the
sake of argument, go with it). Notice that the roof is a kind of "saltbox"
style. There's a 500 lb. snow load acting perpendicular to the longer
slope. The steeper slope has no snow load as we assume that it'll all slide
off. Replace this loading system with an equivalent force and couple
moment acting at point O, the midpoint of the building's base.
F₁
F₂
500
LB.
20'
O
*
10'
*
10'
*
10'
h
h
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