FS F4 F3 F1 Pivot F6 F2 If the forces are: F - 100 N. F 185 N F- 105 N. F. 135 N F- 105 N, and F 105 N the distances are a38 m, b 72 cm, and e 6 cm and the angles are a 24", and 0 43: • The torque of F is0 Nm The torque of F, is 7.03 Nm The torque of F, is 5.755336 Nm • The torque of F is-9.72 Nm. • The torque of is 7.56 Nm. * The torque of Fe is 4.296589 Nm.
FS F4 F3 F1 Pivot F6 F2 If the forces are: F - 100 N. F 185 N F- 105 N. F. 135 N F- 105 N, and F 105 N the distances are a38 m, b 72 cm, and e 6 cm and the angles are a 24", and 0 43: • The torque of F is0 Nm The torque of F, is 7.03 Nm The torque of F, is 5.755336 Nm • The torque of F is-9.72 Nm. • The torque of is 7.56 Nm. * The torque of Fe is 4.296589 Nm.
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Transcribed Image Text:F5
F4
F3
F1
Pivot
a.
F6
F2
If the forces ate: F - 100 N. F- 185 N, F - 105 N, F. 135 N F- 105 N, and Fa 105 N
the distances are a 38 cm, b 7.2 cm, and c 6 cm
and the angles are: a 24°, and 0 43:
• The torque ofF iso
Nm.
• The torque of F, is 7.03
Nm
* The torque of F is 5.755336
N.m.
• The torque of F is-9.72
N.m.
• The torque of F is 7.56
Nm.
* The torque of Fe is 4.296589
N.m.
• The net torque on the beam is 14.921925
Nm.
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