FRQ 1 A graphing calculator is required for the following problem. (0, 10) (-3, 1) (3, 1) Let f(x) = log(x² + 1), g(x) = 10 – x², and R be the region bounded by the graphs of f and g, as shown above. a) Find the volume of the solid generated when R is revolved about the horizontal line y = 10. b) Region R is the base of a solid. For this solid, each cross section perpendicular to the x-axis is an isosceles right triangle with a leg in R. Find the volume of the solid. c) The horizontal line y = 1 divides region R into two regions such that the ratio of the area of the larger region to the area of the smaller region is k:1. Find the value of k.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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1:28 PM Sun May 9
* 77%
FRQ 1
A graphing calculator is required for the following problem.
10
(0, 10)
-5-
(-3, 1)
(3, 1)
-5
Let f(x) = log(x + 1), g(x) = 10 - x², and R be the region bounded by the graphs of f and g, as shown
above.
a) Find the volume of the solid generated when R is revolved about the horizontal line y = 10.
%3D
b) Region R is the base of a solid. For this solid, each cross section perpendicular to the x-axis is an
isosceles right triangle with a leg in R. Find the volume of the solid.
c) The horizontal line y
larger region to the area of the smaller region is k:1. Find the value of k.
1 divides region R into two regions such that the ratio of the area of the
Transcribed Image Text:1:28 PM Sun May 9 * 77% FRQ 1 A graphing calculator is required for the following problem. 10 (0, 10) -5- (-3, 1) (3, 1) -5 Let f(x) = log(x + 1), g(x) = 10 - x², and R be the region bounded by the graphs of f and g, as shown above. a) Find the volume of the solid generated when R is revolved about the horizontal line y = 10. %3D b) Region R is the base of a solid. For this solid, each cross section perpendicular to the x-axis is an isosceles right triangle with a leg in R. Find the volume of the solid. c) The horizontal line y larger region to the area of the smaller region is k:1. Find the value of k. 1 divides region R into two regions such that the ratio of the area of the
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