(From Unit 2, Lesson '12.) Equation 1: y = 3x + 8 Equation 2: 2x - y = -6 %3D 10. Here are two equations: Without using graphing technology: a. Find a point that is a solution to Equation 1 but not a solution to Equation 2. 4 2 b. Find a point that is a solution to Equation 2 but not a solution to -6 -4 -2 Equation 1. -2 -4 C. Graph the two equations. d. Find a point that is a solution to both equations. (From Unit 2, Lesson 12.)

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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(From Unit 2, Lesson '12.)
Equation 1: y = 3x + 8
Equation 2: 2x -y = -6
10. Here are two equations:
Without using graphing technology:
a. Find a point that is a solution to
Equation 1 but not a solution to
Equation 2.
4
b. Find a point that is a solution to
Equation 2 but not a solution to
-6
-4
-2
2
4
Equation 1.
-2
c. Graph the two equations.
-4
d. Find a point that is a solution to both
equations.
(From Unit 2, Lesson 12.)
Transcribed Image Text:(From Unit 2, Lesson '12.) Equation 1: y = 3x + 8 Equation 2: 2x -y = -6 10. Here are two equations: Without using graphing technology: a. Find a point that is a solution to Equation 1 but not a solution to Equation 2. 4 b. Find a point that is a solution to Equation 2 but not a solution to -6 -4 -2 2 4 Equation 1. -2 c. Graph the two equations. -4 d. Find a point that is a solution to both equations. (From Unit 2, Lesson 12.)
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