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(From Unit 2, Lesson '12.) Equation 1: y = 3x + 8 Equation 2: 2x - y = -6 %3D 10. Here are two equations: Without using graphing technology: a. Find a point that is a solution to Equation 1 but not a solution to Equation 2. 4 2 b. Find a point that is a solution to Equation 2 but not a solution to -6 -4 -2 Equation 1. -2 -4 C. Graph the two equations. d. Find a point that is a solution to both equations. (From Unit 2, Lesson 12.)

(From Unit 2, Lesson '12.) Equation 1: y = 3x + 8 Equation 2: 2x - y = -6 %3D 10. Here are two equations: Without using graphing technology: a. Find a point that is a solution to Equation 1 but not a solution to Equation 2. 4 2 b. Find a point that is a solution to Equation 2 but not a solution to -6 -4 -2 Equation 1. -2 -4 C. Graph the two equations. d. Find a point that is a solution to both equations. (From Unit 2, Lesson 12.)

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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(From Unit 2, Lesson '12.) Equation 1: y = 3x + 8 Equation 2: 2x -y = -6 10. Here are two equations: Without using graphing technology: a. Find a point that is a solution to Equation 1 but not a solution to Equation 2. 4 b. Find a point that is a solution to Equation 2 but not a solution to -6 -4 -2 2 4 Equation 1. -2 c. Graph the two equations. -4 d. Find a point that is a solution to both equations. (From Unit 2, Lesson 12.)
Transcribed Image Text:(From Unit 2, Lesson '12.) Equation 1: y = 3x + 8 Equation 2: 2x -y = -6 10. Here are two equations: Without using graphing technology: a. Find a point that is a solution to Equation 1 but not a solution to Equation 2. 4 b. Find a point that is a solution to Equation 2 but not a solution to -6 -4 -2 2 4 Equation 1. -2 c. Graph the two equations. -4 d. Find a point that is a solution to both equations. (From Unit 2, Lesson 12.)
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