From the values given for ∆H° and ∆S°, calculate ∆G° foreach of the following reactions at 298 K. If the reactionis not spontaneous under standard conditions at 298 K,at what temperature (if any) would the reaction becomespontaneous?(a) 2 PbS1s2 + 3 O21g2 ¡ 2 PbO1s2 + 2 SO21g2∆H ° = -844 kJ; ∆S° = -165 J>K(b) 2 POCl31g2 ¡ 2 PCl31g2 + O21g2∆H° = 572 kJ; ∆S° = 179 J>K

Q: What is K for a reaction if ∆G° =-269.9 kJ/mol at 25°C? (R = 8.314 J/mol ･ K)

A: Answer :-  K = 2.0 × 1047 the equilibrium constant, K for the reaction = 2.0 × 1047…

Q: Calculate ∆H°, ∆S° and ∆G° at 298.15 K for the reaction H2 (g)+F2 (g)→2HF(g)

A: We know , Substance  ∆H°(kj/mol) ∆S° (j/mol K) ∆G° (kj/mol) H2(g) 0 130.58 0 F2(g) 0 202.7 0…

Q: The reaction A(g) ∆ B(g) has an equilibrium constant of5.8 and under certain conditions has Q = 336.…

A: Given that : Equilibrium constant Kc = 5.8. It means that ∆G° < 1. Hence, ∆G° is negative.

Q: A student places a piece of solid iron into a solution containing copper(II) ions. 7 (a) Write the…

A:

Q: For a certain reaction at 15°C, ∆H = −10.5 kJ/mol and ∆S = 30. J/mol•K. Calculate ∆G for the…

A: ∆G is the change in gibbs free energy. The value of ∆G is given by following expression :  ∆G = ∆H -…

Q: Define spontaneity of a reaction in terms of ∆G. Determine if a process is spontaneous based on…

A:

Q: At 560 K, ∆G° = -28.9 kJ/mol for the reaction A (g) + 2 B (g) → 3 C (g). If the partial pressures of…

A:

Q: 1) Calculate ΔH0rxn , ΔS0rxn and ΔG0rxn for the formation of ammonia gas from nitrogen gas and…

A: Here we are required to Gibbs free energy for the given reaction .

Q: Determine ∆G° for a reaction when ∆G = -88.9 kJ/mol and Q = 0.043 at 298 K. (R = 8.314 J/mol ･ K)

A: The objective of this question is to calculate the standard Gibbs free energy change (∆G°) for a…

Q: Determine ∆G° for a reaction when ∆G = -122.6 kJ/mol and Q = 0.043 at 298 K. (R = 8.314 J/mol ･ K)

A: The free energy change of the reaction is = -122.6 kJ/mol The temperature of the reaction is = 298 K…

Q: Determine the equilibrium constant for the following reaction at 298 K to one decimal point. SO3(g)…

A: We know that change in the standard Gibbs free energy is equal to the product of gas constant ,…

Q: a) What is K for a reaction if ∆G° =151.6 kJ/mol at 25.0 °C? (R = 8.314 J/mol ･ K) b) For the…

A: We know- ΔG = ΔG° + RT ln QandΔGo=-RTlnK now we have to rearrange the equation- ΔG = ΔG° + RT ln QΔG…

Q: The neutralization of a strong acid and strong base has an enthalpy change, ∆H°, = -55.9 kJ/mol. The…

A: The relationship between the ΔG0 and equilibrium constant is given by  RTln(K) = -ΔG0  where R = gas…

Q: Determine ∆G° for a reaction when ∆G = -181.2 kJ/mol and Q = 0.043 at 298 K. (R = 8.314 J/mol ･ K)

A: Please find the attachment

Q: What is K for a reaction if ∆G° =-164.6 kJ/mol at 25 °C (or 298 K)? (R = 8.314 J/mol ･ K)

A: Thermodynamics can be defined as a branch of chemistry in which we deal with the study of work, heat…

Q: Is it true that if ∆G=0 then reaction is at equilibrium and no net reaction will occur.

A: Yes, it is true. When ∆G=0 a reaction is said to be at equilibrium. Equilibrium does not mean equal…

Q: When the reaction FeO (s) + CO (g) ↔ Fe (s) + CO2 (g) takes place at 600 K, , it is observed that a)…

A: a).  = equilibrium constant at 600°C =  0.900

Q: At what temperature/temperature range does this reaction become spontaneous? Explain your reason.…

A: Given, Br2(l)⇔br2(g)and△H=30.91kJ△s=0.0933kJ/Kwe know that ;△G=△H-T△Swhere, △G= Change in Gibb's…

Q: What is K for a reaction if ∆G° =-232.9 kJ/mol at 25°C (or 298 K)? (R = 8.314 J/mol ･ K)

A: We know that  ∆G° = - RT lnK

Q: At 560 K, ∆G° = -24.7 kJ/mol for the reaction A (g) + 2 B (g) → 3 C (g). If the partial pressures of…

A:

Q: For a specific chemical reaction, ΔH = −254 kJ and ΔS = −86 J K-1. Calculate ΔG at 50 K, 200 K, and…

A:

Q: What is K for a reaction if ∆G° =-292.8 kJ/mol at 25°C? (R = 8.314 J/mol ･ K)

A: Interpretation: The value of K for a reaction, if ∆G° = -292.8 kJ/mol at 25°C is to be determined.

Q: Absolute Entropy at 298 K (J/(K mol)) NO(g) 211 O2(9) 205 NO2(g) 240

A:

Q: At 560 K, ∆G° = -18.1 kJ/mol for the reaction A (g) + 2 B (g) → 3 C (g). If the partial pressures of…

A: Gibbs free energy of the chemical reaction can be expressed as, ∆G=∆Go+RTlnQ where Q is the reaction…

Q: At 560 K, ∆G° = -23.5 kJ/mol for the reaction A (g) + 2 B (g) → 3 C (g). If the partial pressures of…

A:

Q: Given a process with ∆Η = − 250 kilojoules/mol ∆S = - 100 joules/K mol at what temperature (Kelvin)…

A:

Q: What is K for a reaction if ∆G° =-195.9 kJ/mol at 25°C? (R = 8.314 J/mol ･ K)

A:

Q: At 560 K, ∆G° = -39.5 kJ/mol for the reaction A (g) + 2 B (g) → 3 C (g). If the partial pressures of…

A: Answer :- ∆G = 12.7 (kJ/mol) The ∆G for the given reaction at 560 K = 12.7 kJ/mol…

Q: At 560 K, ∆G° = -38.9 kJ/mol for the reaction A (g) + 2 B (g) → 3 C (g). If the partial pressures of…

A: The question is based on the concept of equilibrium. we have to calculate Gibbs free energy change…

Q: The potassium-ion concentration in blood plasma is about 5.0 * 10-3 M, whereas the concentration in…

A:

Q: What is K for a reaction if ∆G° =-273.8 kJ/mol at 25°C? (R = 8.314 J/mol ･ K)

A: Standard Gibbs free energy is related with Equilibrium constant,K as - ∆G° = - RT ln K   Where - ∆G°…

Q: What is K for a reaction if ∆G° =-254.1 kJ/mol at 25°C? (R = 8.314 J/mol ･ K)

A: The most usual method to state about reaction's spontaneity is comparing its Gibbs energy or its…

Q: What is K for a reaction if ∆G° =173.2 kJ/mol at 25.0 °C? (R = 8.314 J/mol ･ K)

A: Given, Standard gibbs free energy (∆G°) = 173.2 kJ/mol = 173.2 × 1000 J/mol = 173200 J/mol…

Q: Calculate the value of the free energy change, ΔG, for the reaction below at 600.0ºC when the…

A: Given reaction is :  2 POCl3 (g) → 2 PCl3 (g) +  O2 (g)  Pressures of POCl3 (g) at 600.0ºC = 20.00…

Q: For the reaction below ∆G° = + 33.0 kJ, ∆H° = + 92.2 kJ, and ∆S° = + 198.7 J/K. Estimate the…

A: We wil use the Gibbs helmholtz equation to calculate the temperature when ∆G is zero. And above this…

Q: What is K for a reaction if ∆G° =-64.2 kJ/mol at 25.0 °C? (R = 8.314 J/mol ･ K)

A:

Q: What must the sign of ∆G be for any spontaneous process

A: Dear student I have given answer to your question in the image format.

Q: At 560 K, ∆G° = -39.9 kJ/mol for the reaction A (g) + 2 B (g) → 3 C (g). If the partial pressures of…

A: Equilibrium constant is defined as ratio of partial pressure of reactant to the partial pressure of…

Q: Which of the following reactions are spontaneous at 298 K? AH = -200 kJ/mol, AS= -1.0 kJ/(mol*K) AH…

A: Recall the following expression for change in Gibbs free energy∆G               ∆G=∆H-T∆SIf for any…

Q: What is K for a reaction if ∆G° =-171.1 kJ/mol at 25°C? (R = 8.314 J/mol ･ K)

A: Gibbs' free energy and equilibrium constant has the following relation ∆G0 =-RT lnKeqm Or, Keqm =…

Q: Calculate ∆S, ∆Ssurr , and ∆Stot when 21 g of Ar (g) at 298 K and 1.5 bar increases in volume from…

A:

Q: At 560 K, ∆G° = -36.3 kJ/mol for the reaction A (g) + 2 B (g) → 3 C (g). If the partial pressures of…

A: Information about the question

Q: For a certain chemical reaction, ∆H° = -35.4 kJ and ∆S° = -85.5 J>K. Calculate ∆G° for the…

A: ∆H°=-35.4KJ         =-35400J∆S° =-85.5J/K  T  =298K