From the two inaccessible but intervisible points A and B, the angles to two triangulation stations C and D were observed as follows. Line CD has a distance of 500m long. Compute the distance of the line AB. Angle САВ 79° 30' DAB 28° 30' DBC 31° 30' DBA 84° 30' D 31°30' 79°30' 28°30' 84°30' A В Hint:

From the two inaccessible but intervisible points A and B, the angles to two triangulation stations C and D were observed as follows. Line CD has a distance of 500m long. Compute the distance of the line AB. Angle САВ 79° 30' DAB 28° 30' DBC 31° 30' DBA 84° 30' D 31°30' 79°30' 28°30' 84°30' A В Hint:

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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No.6 only!!
Q2/B- A rough sketch of the situation is shown in Fig. PABCQP is a closed traverse. Lengths of lines CQ and QP are to be determined. Compute the latitudes and departures as shown in the table. Assume that the length of CQ = L1 and that of QP =L2. Line 12888 PA AB BC CQ QP Length 150 500 300 L₁ L₂ Bearing N10° 15'E N32° 45'E N65° 30'E $50° 30'E S68° 45'W Latitude 147.6 420.52 124.41 0.6361L₁ 0.3624L₂ Departure 26.69 270.49 272.99 0.77164₁ 0.932L₂
Q3): The following data were collected while running a closed traverse ABCDA starting from A toward B. Calculate: Line AB BC CD DA 1- Coordinates of A (Easting and Northing). 2- Azimuth of BC and CD 3- Coordinates of point C 4- Coordinates of point D 5- Linear misclosure 6- Traverse precision Length (m) 330 767 411 727.438 Azimuth 181°25' 263° 32' 17" Point A (fixed) B C D A (calculated) Easting (m) 392.341 N Northing (m) 270.601 D Angles B = 88° 25' C = 85° 10' @
Q.2) Answer ONE from the following: A) Compute the coordinates of the traverse points Q, R, S, and T. ро L 40 m (due N) $(100,100) Pl TAL BC-- 109° 54' و بهتان رقبا متاب - Az 58 m di 60 m 50 m R 35 m (Az. 132° 48') -
A closed traverse shown has the following data: LINES BEARING DISTANCE AB S 15*38' W 24.22 m BC S 69*11' E 15.92 m CD N 57*58' E DA S 80°43' W 1. Find the distance CD in meters. a. 81.20 m b. 34.67 m c. 77.48 m d. 59.01 m 2. Find the distance DA in meters. a. 61.89 m b. 49.18 m c. 50.28 m d. 75.02 m 3. Find the area in a. 512.37 m2 m. b. 1123.61 m2 C. 191.99 m? d. 1315.60 m?
No.5 only!!
HI! HELP ME PLEASE. TYSM.
In order to determine a tunnel between station A and B where the vision was obstructed between them, a traverse was selected to link between these stations. The field measurements of the traverse as in the table below.Calculate the length and the bearing of the tunnel (AB) and the angle * .BAD for setting it out Line |Length(m) Azimuth DA 500 2100 DC 2000 450 СВ 1000 2700 АВ ? ?
AREA MEASUREMENTS W- E U AREA BY DOUBLE MERIDIAN DISTANCE (DMD) Problem 1: In the tabulation are given the adjusted latitudes and adjusted departures of a closed traverse. V Determine the area using DMD method. LINE ADJUSTED LATITUDE ADJUSTED DEPARTURE (+)N (-)S (+)E (-)W Y AB 113.92 388.84 ВС 178.86 285.13 CD 295.88 134.96 DE 164.35 135.39 EF 13.53 251.86 FA 182.95 151.76 SUM +474.74 -474.74 +673.97 -673.97
b)Table 3 shows the data of closed traverse. Table 3 Station Bearing Distance (m)1-2 103o 31' 30” 71.7002-3 196o 26' 50” 73.3003-4 273o 57' 10” 75.2004-5 340o 13' 50” 54.3505-1 55o 18' 40” 54.030 Illustrate a diagram and find; i)The latitude and departure of each line.ii)The adjusted value of latitude and departure for each line. iii)The coordinate for each station, given the coordinate of station1 (N3000, W4000)
· A closed traverse has the following data: Line Length (m) Bearing АВ 152.132 N44°48'W ВС 128.562 N12°35'W CD 155.436 N78°51'E DE 141.657 S16°12'E EA 137.544 S24°53'W a.) Adjust the traverse using compass rule and determine the area using DMD, b.) Adjust the traverse using transit rule and determine the area using DPD.
P2 89°50" 268° 81°35' Y, 185°35' 102°10' 95°5' 80°25' P4 P3 270°30' 90°25' 191°