From the given traverse result:LinesBearingDistance ABS35o30’W44.37m BCN57o15’W137.84m CDN1o45’W12.83m DE?64.86m EA?106.72m Compute the following:The bearing of line DEThe bearing of line EACompute the area of the lot in acres.

Closed traverse ABCDEA is given where bearing of line DE and EA is missing. It has been asking to…

Answered: From the given traverse result: Lines…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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2. A pentagonal lot SIDE AB BC CD DE EA FIND! has the ff. data. DISTANCE (m) 108.20 १४.७० 112.40 AZIMUTH 198°30' 2880 356°30' 42° 20' ? 120.00 ? a) bearing & distance of EA b) area & in hectare C) DMD of BC d) DPD of DE
Determine the interior angles of triangle ABC
A triangular lot has interior angles ABC, with value 44.06°, 54.49°, and 82.01° respectively. What is the angular error of closure? O 33'36" O 0.58 O 33°36' 0'50"
A pentagonal lot has the following data. SIDE AZIMUTH DISTANCE(M) AB 198° 30' 108.20 BC 288° 98.60 CD 356° 30' 112.40 DE 42° 20' 120.00 EA ? ? Find the following: a) bearing and distance (m) of line EA b) area of the lot ( in m2 ) and (in hectare) c) DMD (Double Meridian Distance) of line BC d) DPD (Doubel Parallel Distance) of line DE Kindly show a full and detailed solution, thank you!
Lot ABCDEF is a close traverse (clockwise) in the form of a regular hexagon. If the bearing of AB is N 28° 40' W, what is the bearing of BC? CD? DE? EF? AF?
pls show solution and figure
LINE AB BC CD DE EA DISTANCE 647.25 203.03 720.35 610.24 275.13 balancing the traverse by using transit rule BEARING S 53.08⁰ E $ 5.68⁰ E N 15.53⁰ E N 75.41⁰ W S 26.16⁰ W
11. ADJUSTMENT OF LENGTHS AND BEARINGS. Given in the accom- panying tabulation tures for a property survey. and adjusted bearing of each course. Tabulate all given and computed values accordingly. are the adjusted latitudes and depar- Determine the adjusted length ADJUSTED LATITUDE ADJUSTED DEPARTURE COURSE +N +E - W 117.09 176.83 1-2 1 03.82 2-3 3.67 3-4 166.64 20.34 4-5 27.65 224.05 5-1 86.80 90.21 Sums +194.29 -194.29 +314.26 -314.26 (ENL) ESL) (ΣΕD ) (EWD)
How to determine the distance of the other end of the dividing line D along the side AB measured from A?
Compute by DMDs the area in hectares within a closed-polygon traverse ABCDEFA by placing the X and Y axes through the most southerly and most westerly stations, respectively. Departures and latitudes (in meters) follow.AB: E dep. = 30, N lat. = 40; BC: E dep. = 70, N lat. = 10; CD: E dep. = 30, S lat. = 50; DE: W dep. = 60, S lat. = 40; EF: W dep. = 90, S lat. = 30; FA: E dep. = 20, N lat. = 70
A clockwise traverse ABCDEA was surveyed Find the length and direction of line AD Line AB BC CD DA Length(m) 101.01 140.24 99.27 C B D A E Direction 00°00'00" 77°55'30" 173°37'20" D D 137.137 11.027 L sine L 101.01 29.337 -98.656 L cose AD=151.515m,0=257°55′37" O AD=144.735m,0=77°55′37″ O AD=151.515m,0=77°55′37" O AD=145.735m,0=257°55'37" AD=144.735m,9=257°55′37″ O
Compute the area using Double meridian diatance or triangulation Length (meters) Com. Com.Dep Bearing Latitude N S(-) Line arture E W(-) N 5° 30' E N 46° 02' E S 67° 38 'E S12° 25 'E S 83° 44'W N 55° 09'W АВ 495.85 BC 850.62 CD 855.45 DE 1020.87 EF 1117.26 FA 660.08 Total 5000.13

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Lines	Bearing	Distance
AB	S35^o30’W	44.37m
BC	N57^o15’W	137.84m
CD	N1^o45’W	12.83m
DE	?	64.86m
EA	?	106.72m

From the given traverse result: Lines Bearing Distance AB S35o30’W 44.37m BC N57o15’W 137.84m CD N1o45’W 12.83m DE ? 64.86m EA ? 106.72m Compute the following: The bearing of line DE The bearing of line EA