From the following reaction: Mno2 + 4H* + 2CI → Mn2+ + Cl2 + 2 H20 (a) Which atom is reducing? fill in blank (b) Which atom is oxidizing? fill in blank (c) Which atom is the reducing agent? fill in blank (d) Which atom is the oxidizing agent? fill in blank
From the following reaction: Mno2 + 4H* + 2CI → Mn2+ + Cl2 + 2 H20 (a) Which atom is reducing? fill in blank (b) Which atom is oxidizing? fill in blank (c) Which atom is the reducing agent? fill in blank (d) Which atom is the oxidizing agent? fill in blank
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Understanding Redox Reactions
**From the following reaction:**
\[ \text{MnO}_2 + 4\text{H}^+ + 2\text{Cl}^- \rightarrow \text{Mn}^{2+} + \text{Cl}_2 + 2 \text{H}_2\text{O} \]
(a) **Which atom is reducing?**
*fill in blank*
(b) **Which atom is oxidizing?**
*fill in blank*
(c) **Which atom is the reducing agent?**
*fill in blank*
(d) **Which atom is the oxidizing agent?**
*fill in blank*
### Explanation of Redox Terms:
1. **Reduction** is the gain of electrons by an atom, ion, or molecule.
2. **Oxidation** is the loss of electrons by an atom, ion, or molecule.
3. **Reducing Agent** is the substance that donates electrons in a redox reaction and gets oxidized.
4. **Oxidizing Agent** is the substance that accepts electrons in a redox reaction and gets reduced.
### Steps to Identify:
- Identify the changes in oxidation states of the elements.
- Determine which elements are gaining or losing electrons.
- Identify the oxidizing and reducing agents based on electron transfer.
### Detailed Explanation of the Reaction:
- \( \text{MnO}_2 \) (Manganese dioxide) is converted to \( \text{Mn}^{2+} \) (Manganese ion).
- \( \text{Cl}^- \) (Chloride ion) is converted to \( \text{Cl}_2 \) (Chlorine gas).
Using these details, determine the elements involved in oxidation and reduction to fill in the blanks.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F25d2fd2d-41da-4a28-950b-7afe9a6e5b79%2Feacad09f-b12a-4eac-a72e-e1ec552d8a14%2Fspvfbq8_processed.png&w=3840&q=75)
Transcribed Image Text:### Understanding Redox Reactions
**From the following reaction:**
\[ \text{MnO}_2 + 4\text{H}^+ + 2\text{Cl}^- \rightarrow \text{Mn}^{2+} + \text{Cl}_2 + 2 \text{H}_2\text{O} \]
(a) **Which atom is reducing?**
*fill in blank*
(b) **Which atom is oxidizing?**
*fill in blank*
(c) **Which atom is the reducing agent?**
*fill in blank*
(d) **Which atom is the oxidizing agent?**
*fill in blank*
### Explanation of Redox Terms:
1. **Reduction** is the gain of electrons by an atom, ion, or molecule.
2. **Oxidation** is the loss of electrons by an atom, ion, or molecule.
3. **Reducing Agent** is the substance that donates electrons in a redox reaction and gets oxidized.
4. **Oxidizing Agent** is the substance that accepts electrons in a redox reaction and gets reduced.
### Steps to Identify:
- Identify the changes in oxidation states of the elements.
- Determine which elements are gaining or losing electrons.
- Identify the oxidizing and reducing agents based on electron transfer.
### Detailed Explanation of the Reaction:
- \( \text{MnO}_2 \) (Manganese dioxide) is converted to \( \text{Mn}^{2+} \) (Manganese ion).
- \( \text{Cl}^- \) (Chloride ion) is converted to \( \text{Cl}_2 \) (Chlorine gas).
Using these details, determine the elements involved in oxidation and reduction to fill in the blanks.
![### Spectator Ions in a Chemical Reaction
**Question:** What ions will be spectator ions from the following reaction?
\[
\text{Cl}_2 (g) + 2 \text{NaBr} (aq) \rightarrow \text{Br}_2(l) + 2 \text{NaCl} (aq)
\]
*(Check all that apply)*
- [ ] Br\(_2\)(l)
- [ ] NaCl (aq)
- [ ] Cl\(_2\) (g)
- [ ] Br\(^-\) (aq)
- [ ] Cl\(^-\) (aq)
- [ ] NaBr (aq)
- [ ] Na\(^+\) (aq)
**Explanation:**
In a chemical reaction, spectator ions are ions that do not take part in the actual chemical change but are present in the reaction mixture. To identify the spectator ions, we can look at the ionic equations of the reactants and products.
### Breakdown of the Reaction:
1. **Total Ionic Equation:**
\[
\text{Cl}_2 (g) + 2 \text{Na}^+ (aq) + 2 \text{Br}^- (aq) \rightarrow \text{Br}_2 (l) + 2 \text{Na}^+ (aq) + 2 \text{Cl}^- (aq)
\]
2. **Net Ionic Equation:**
\[
\text{Cl}_2 (g) + 2 \text{Br}^- (aq) \rightarrow \text{Br}_2 (l) + 2 \text{Cl}^- (aq)
\]
From this breakdown, the sodium ions (\(\text{Na}^+\)) remain unchanged on both sides of the equation and thus are spectator ions. Identifying the spectator ions helps in understanding the actual species participating in the reaction.
### Correct Answers:
- [ ] Br\(_2\)(l)
- [ ] NaCl (aq)
- [ ] Cl\(_2\) (g)
- [x] Br\(^-\) (aq)
- [ ] Cl\(^-\) (aq)
- [ ] NaBr (aq)
- [x] Na\(^+\) (aq)
The correct spectator ions from the provided choices are the bromide ion (Br\(^-\)) and the sodium ion (Na\(^+\)).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F25d2fd2d-41da-4a28-950b-7afe9a6e5b79%2Feacad09f-b12a-4eac-a72e-e1ec552d8a14%2Frzs5ol_processed.png&w=3840&q=75)
Transcribed Image Text:### Spectator Ions in a Chemical Reaction
**Question:** What ions will be spectator ions from the following reaction?
\[
\text{Cl}_2 (g) + 2 \text{NaBr} (aq) \rightarrow \text{Br}_2(l) + 2 \text{NaCl} (aq)
\]
*(Check all that apply)*
- [ ] Br\(_2\)(l)
- [ ] NaCl (aq)
- [ ] Cl\(_2\) (g)
- [ ] Br\(^-\) (aq)
- [ ] Cl\(^-\) (aq)
- [ ] NaBr (aq)
- [ ] Na\(^+\) (aq)
**Explanation:**
In a chemical reaction, spectator ions are ions that do not take part in the actual chemical change but are present in the reaction mixture. To identify the spectator ions, we can look at the ionic equations of the reactants and products.
### Breakdown of the Reaction:
1. **Total Ionic Equation:**
\[
\text{Cl}_2 (g) + 2 \text{Na}^+ (aq) + 2 \text{Br}^- (aq) \rightarrow \text{Br}_2 (l) + 2 \text{Na}^+ (aq) + 2 \text{Cl}^- (aq)
\]
2. **Net Ionic Equation:**
\[
\text{Cl}_2 (g) + 2 \text{Br}^- (aq) \rightarrow \text{Br}_2 (l) + 2 \text{Cl}^- (aq)
\]
From this breakdown, the sodium ions (\(\text{Na}^+\)) remain unchanged on both sides of the equation and thus are spectator ions. Identifying the spectator ions helps in understanding the actual species participating in the reaction.
### Correct Answers:
- [ ] Br\(_2\)(l)
- [ ] NaCl (aq)
- [ ] Cl\(_2\) (g)
- [x] Br\(^-\) (aq)
- [ ] Cl\(^-\) (aq)
- [ ] NaBr (aq)
- [x] Na\(^+\) (aq)
The correct spectator ions from the provided choices are the bromide ion (Br\(^-\)) and the sodium ion (Na\(^+\)).
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