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From the data, 100 (1 + 0.1 jw) 1-0.0004² + jo.028 TF (W) = 100 (1 + jw) 10 TF(W) = Factor It jw TF (W) 1 I+jW = By comparing 080, zero is located at w/= 10 rad sec 1+ (jw)² jw (50)2 + 100 (1 + jw) and pole is located at W₂ = = 2 + jw 50² 35.71 2 1+ (jw) ² + 2 & (jw) wzg Each zero contribute slope of +20dB/dec and +90° phase. where as each pole of order 2 can -18⁰⁰ phase. contribute -40dB/dec slope and 35.71 50 rad/sec with order of 2 slope phase +2010/460/+90° -4013/11/-188 Resultant slope phase 20 ds/dec/+90° + -20453/dc/-90 dB Bode plot: Magnitude M= |TF (W) = 100 √ 1 + (0-10)²2 0.028W²+(1-0.0004)

From the data, 100 (1 + 0.1 jw) 1-0.0004² + jo.028 TF (W) = 100 (1 + jw) 10 TF(W) = Factor It jw TF (W) 1 I+jW = By comparing 080, zero is located at w/= 10 rad sec 1+ (jw)² jw (50)2 + 100 (1 + jw) and pole is located at W₂ = = 2 + jw 50² 35.71 2 1+ (jw) ² + 2 & (jw) wzg Each zero contribute slope of +20dB/dec and +90° phase. where as each pole of order 2 can -18⁰⁰ phase. contribute -40dB/dec slope and 35.71 50 rad/sec with order of 2 slope phase +2010/460/+90° -4013/11/-188 Resultant slope phase 20 ds/dec/+90° + -20453/dc/-90 dB Bode plot: Magnitude M= |TF (W) = 100 √ 1 + (0-10)²2 0.028W²+(1-0.0004)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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From the data, TF (W) = Factor It jw 1 I+jW TF (∞) = 100 (1+ JW) 10 TF (W) + jw 50² 35.71 ) rad Sec By comparing 0%, zero is located at w/= 10 rad sec At W₁=10% and pole is located at W₂ = 50 rad/sec with order at 2 2 Each zero contribute slope of +20dB/dec and +90° phase. where as each pole of order 2 can -18⁰⁰ phase. contribute -40dB/dec slope and 43 dB 100 (1 + 0.1 jw) 1-0.0004 w² + jo.028 = 40dB +98 1+ (jw)² jw (50)2 + ⇒ 100 (₁ + jw) 2 1+ (jw) ² wzg slope phase +2018/dec/+90° -40dB/des/-188 Bode plot: Magnitude M= |TF(W) = 100 √ 1 + (0-10) 2 (0.0284³²+ (1-80048) ( 20 log/100) :: MdB M = 20 log (100) + 20 g √ [+ (6-1×10) ²) B 35.71 + 2 & (jw) sec MdB = 43 dB at W₁ = 10 rad +20dB/dec MdB = Magnitude plot W₁=10 phase plot (0) Resultant slope phase +2010/4/198 -2018/407/-18 dB W₁=10 w=50 |W₂=50 -90° -20dB/dec >W approximate phase
Transcribed Image Text:From the data, TF (W) = Factor It jw 1 I+jW TF (∞) = 100 (1+ JW) 10 TF (W) + jw 50² 35.71 ) rad Sec By comparing 0%, zero is located at w/= 10 rad sec At W₁=10% and pole is located at W₂ = 50 rad/sec with order at 2 2 Each zero contribute slope of +20dB/dec and +90° phase. where as each pole of order 2 can -18⁰⁰ phase. contribute -40dB/dec slope and 43 dB 100 (1 + 0.1 jw) 1-0.0004 w² + jo.028 = 40dB +98 1+ (jw)² jw (50)2 + ⇒ 100 (₁ + jw) 2 1+ (jw) ² wzg slope phase +2018/dec/+90° -40dB/des/-188 Bode plot: Magnitude M= |TF(W) = 100 √ 1 + (0-10) 2 (0.0284³²+ (1-80048) ( 20 log/100) :: MdB M = 20 log (100) + 20 g √ [+ (6-1×10) ²) B 35.71 + 2 & (jw) sec MdB = 43 dB at W₁ = 10 rad +20dB/dec MdB = Magnitude plot W₁=10 phase plot (0) Resultant slope phase +2010/4/198 -2018/407/-18 dB W₁=10 w=50 |W₂=50 -90° -20dB/dec >W approximate phase
d 19, Plot the Bode plot (magnitude and phase) of the following transfer function using graphical techniques. TF (w) - 100(1+0.1jw) (1-0.0004w² + j0.028)
Transcribed Image Text:d 19, Plot the Bode plot (magnitude and phase) of the following transfer function using graphical techniques. TF (w) - 100(1+0.1jw) (1-0.0004w² + j0.028)
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