From the above table calculate the probability that a woman has: 1. Two living children 2. A number of living children between 3 and 6 3. <6 living children 4. Exactly 6 living children 5. At least 4 living children 6. Maximum of 3 living children

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This is a new assignment about the IL of probabilty.1
umulative
Number of
living Frequency
children
Proportion
Probability
Proportion
or
Cumulative
Probability
156
0.089
0.089
1
228
0.129
0.218
2
310
0.176
0.394
3
316
0.179
0.574
4
262
0.149
0.722
197
0.112
0.834
159
0.09
0.924
7
69
0.039
0.964
8.
45
0.026
0.989
15
0.009
0.998
10
0.002
Total
1761
1
From the above table calculate the probability that a woman has:
1. Two living children
2. A number of living children between 3 and 6
3. < 6 living children
4. Exactly 6 living children
5. At least 4 living children
6. Maximum of 3 living children
7. If we consider this a representative sample of the country women aged 15-
49 years, and we obtain another representative sample of 500 women.
How many of these women would have 2 or 3 children?
Transcribed Image Text:This is a new assignment about the IL of probabilty.1 umulative Number of living Frequency children Proportion Probability Proportion or Cumulative Probability 156 0.089 0.089 1 228 0.129 0.218 2 310 0.176 0.394 3 316 0.179 0.574 4 262 0.149 0.722 197 0.112 0.834 159 0.09 0.924 7 69 0.039 0.964 8. 45 0.026 0.989 15 0.009 0.998 10 0.002 Total 1761 1 From the above table calculate the probability that a woman has: 1. Two living children 2. A number of living children between 3 and 6 3. < 6 living children 4. Exactly 6 living children 5. At least 4 living children 6. Maximum of 3 living children 7. If we consider this a representative sample of the country women aged 15- 49 years, and we obtain another representative sample of 500 women. How many of these women would have 2 or 3 children?
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