From Step 3: Why does this circuit use a diode at D3 instead of a pull-up resistor? Select the best answer. Diodes are directional components that only allow current to flow one way. Without a diode at D3, current could flow backward through the circuit, preventing it from working correctly. When SW1 is not pressed, a jumper wire or resistor would still allow the junction at the low side of SW1 to be pulled high, causing the red LED at D1 to light up. We have not used basic diodes yet this quarter. This allows them to be included in the lab activities. When SW1 is pressed, a resistor would pull the junction with D1 low, causing the red LED at D1 not to light at the moment it is supposed to.
From Step 3: Why does this circuit use a diode at D3 instead of a pull-up resistor? Select the best answer. Diodes are directional components that only allow current to flow one way. Without a diode at D3, current could flow backward through the circuit, preventing it from working correctly. When SW1 is not pressed, a jumper wire or resistor would still allow the junction at the low side of SW1 to be pulled high, causing the red LED at D1 to light up. We have not used basic diodes yet this quarter. This allows them to be included in the lab activities. When SW1 is pressed, a resistor would pull the junction with D1 low, causing the red LED at D1 not to light at the moment it is supposed to.
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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![### Motor Warning Light Instructions
**Step 3: Integrating a Red LED**
In this step, you will incorporate a red LED (D1 in the main schematic) into the circuit setup with a series resistance of 500Ω (denoted as R1 in the main schematic). The method to achieve a resistance of 500Ω is flexible and up to your choice.
#### Schematic Diagram:
The diagram below illustrates the circuit configuration:
![Schematic Diagram](path/to/your/image)
- **Power Supply Block (PSB)**: 5 V
- **Blue LED (D2)**
- **Diode (D3)**: 1N4007
- **Red LED (D1)**
- **Resistors**: R1 (500Ω), R3 (10 kΩ)
- **Switch (SW1)**
#### Circuit Explanation:
The setup involves a power supply block (PSB) providing 5V to the circuit. Two LEDs (D2 in blue and D1 in red) are connected, and a diode (D3) is placed in the circuit to control the current flow. The resistors R1 and R3 are used to manage the current through the LEDs.
#### Interactive Questions:
1. **What happens now when SW1 is pressed (and the PSB is turned on)?**
2. **What happens if you turn the diode at D3 around?** (Remember to place it back in the correct orientation afterward.)
3. **Why does this circuit use a diode at D3 instead of a pull-up resistor?** (Consider what would occur if a resistor were used instead of the diode.)
---
These questions are designed to help you understand the implications of various components and their configurations within the circuit. Experiment with the circuit by following the step-by-step instructions, and reflect on the significance of each component's placement and function.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F10720d57-2b70-4cbe-a273-53d8d7f1ea5d%2Fde4f9aee-017d-4897-9bcb-4bef7b1ce652%2Fa155dov_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Motor Warning Light Instructions
**Step 3: Integrating a Red LED**
In this step, you will incorporate a red LED (D1 in the main schematic) into the circuit setup with a series resistance of 500Ω (denoted as R1 in the main schematic). The method to achieve a resistance of 500Ω is flexible and up to your choice.
#### Schematic Diagram:
The diagram below illustrates the circuit configuration:
![Schematic Diagram](path/to/your/image)
- **Power Supply Block (PSB)**: 5 V
- **Blue LED (D2)**
- **Diode (D3)**: 1N4007
- **Red LED (D1)**
- **Resistors**: R1 (500Ω), R3 (10 kΩ)
- **Switch (SW1)**
#### Circuit Explanation:
The setup involves a power supply block (PSB) providing 5V to the circuit. Two LEDs (D2 in blue and D1 in red) are connected, and a diode (D3) is placed in the circuit to control the current flow. The resistors R1 and R3 are used to manage the current through the LEDs.
#### Interactive Questions:
1. **What happens now when SW1 is pressed (and the PSB is turned on)?**
2. **What happens if you turn the diode at D3 around?** (Remember to place it back in the correct orientation afterward.)
3. **Why does this circuit use a diode at D3 instead of a pull-up resistor?** (Consider what would occur if a resistor were used instead of the diode.)
---
These questions are designed to help you understand the implications of various components and their configurations within the circuit. Experiment with the circuit by following the step-by-step instructions, and reflect on the significance of each component's placement and function.
![### From Step 3:
#### Why does this circuit use a diode at D3 instead of a pull-up resistor?
#### Select the best answer.
- **Option 1:**
- **Answer:** Diodes are directional components that only allow current to flow one way. Without a diode at D3, current could flow backward through the circuit, preventing it from working correctly.
- **Option 2:**
- **Answer:** When SW1 is not pressed, a jumper wire or resistor would still allow the junction at the low side of SW1 to be pulled high, causing the red LED at D1 to light up.
- **Option 3:**
- **Answer:** We have not used basic diodes yet this quarter. This allows them to be included in the lab activities.
- **Option 4:**
- **Answer:** When SW1 is pressed, a resistor would pull the junction with D1 low, causing the red LED at D1 not to light at the moment it is supposed to.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F10720d57-2b70-4cbe-a273-53d8d7f1ea5d%2Fde4f9aee-017d-4897-9bcb-4bef7b1ce652%2Fdq0lu0g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### From Step 3:
#### Why does this circuit use a diode at D3 instead of a pull-up resistor?
#### Select the best answer.
- **Option 1:**
- **Answer:** Diodes are directional components that only allow current to flow one way. Without a diode at D3, current could flow backward through the circuit, preventing it from working correctly.
- **Option 2:**
- **Answer:** When SW1 is not pressed, a jumper wire or resistor would still allow the junction at the low side of SW1 to be pulled high, causing the red LED at D1 to light up.
- **Option 3:**
- **Answer:** We have not used basic diodes yet this quarter. This allows them to be included in the lab activities.
- **Option 4:**
- **Answer:** When SW1 is pressed, a resistor would pull the junction with D1 low, causing the red LED at D1 not to light at the moment it is supposed to.
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