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From solution of equation for Unsteady state conduction of heat: y 2√at T = T₁ at y> 0 and t = 0 T = Ts at y = 0 and t > 0 T →>> Ti at y → ∞ and t > 0 T T₁ = (Ts T₁) erfc(- - Prove that the heat flux at the surface of the solid (y = 0): qy = 0 k(Ts - Ti) (πατ

From solution of equation for Unsteady state conduction of heat: y 2√at T = T₁ at y> 0 and t = 0 T = Ts at y = 0 and t > 0 T →>> Ti at y → ∞ and t > 0 T T₁ = (Ts T₁) erfc(- - Prove that the heat flux at the surface of the solid (y = 0): qy = 0 k(Ts - Ti) (πατ

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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From solution of equation for Unsteady state conduction of heat: y T - Ti = (Ts - T₁) erfc(- 2√at T = Ti at y> 0 and t = 0 Ts at y = 0 and t > 0 T = T →>>> Ti at y → ∞o and t > 0 Prove that the heat flux at the surface of the solid (y=0): k(Ts - Ti) Vπατ qy = 0 =
Transcribed Image Text:From solution of equation for Unsteady state conduction of heat: y T - Ti = (Ts - T₁) erfc(- 2√at T = Ti at y> 0 and t = 0 Ts at y = 0 and t > 0 T = T →>>> Ti at y → ∞o and t > 0 Prove that the heat flux at the surface of the solid (y=0): k(Ts - Ti) Vπατ qy = 0 =
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