From same problem directly above, find the probability that exactly 11 patients will recover? From same problem directly above, find the probability that less than or equal to 10 patients will ener? From the same problem directly above, find the probability that more than 12 patients will recover?

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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From same problem directily above. find the probability that exactly 11 patients
will recover?
From same problem directly above, find the probability that less than or equal to
10 patients willireenver?
From the samne problem directly above, find the probability that more than 12
patients will recover?
Transcribed Image Text:From same problem directily above. find the probability that exactly 11 patients will recover? From same problem directly above, find the probability that less than or equal to 10 patients willireenver? From the samne problem directly above, find the probability that more than 12 patients will recover?
Step 1
Solution:
Let X be the number of recovered patients and n be the sample number of patients under an
observation.
From the given information, probability that a patient recovers from a delicate heart operation is 0.60
and n=20.
Step 2
Here, patients are independent and probability of success is constant. Hence, X follows binomial
distribution with parameters n=20 and p=0.60.
Then, the mean of the recover patients is
Меan %3D пр
= 20x0.60
=12
Step 3
The standard deviation of the recovered patients is
S tan dard deviation= Jnp(1- p)
20(0.60)(1-0.60)
=V4.8
= 2.19
Transcribed Image Text:Step 1 Solution: Let X be the number of recovered patients and n be the sample number of patients under an observation. From the given information, probability that a patient recovers from a delicate heart operation is 0.60 and n=20. Step 2 Here, patients are independent and probability of success is constant. Hence, X follows binomial distribution with parameters n=20 and p=0.60. Then, the mean of the recover patients is Меan %3D пр = 20x0.60 =12 Step 3 The standard deviation of the recovered patients is S tan dard deviation= Jnp(1- p) 20(0.60)(1-0.60) =V4.8 = 2.19
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