From ERROR FUNCTION topic assigned to us.. please kindly do me a favor on making the argument part of our paper 6.) ARGUMENTS present your argument on how you can modify the solution and if such alteration will be done, depending on the conditions, how will it affect the solution you have. For other topics, some conditions will provide an entirely new function. our topic is all about ERROR FUNCTIONS in Advance Engineering Mathematics.

From ERROR FUNCTION topic assigned to us.. please kindly do me a favor on making the argument part of our paper 6.) ARGUMENTS present your argument on how you can modify the solution and if such alteration will be done, depending on the conditions, how will it affect the solution you have. For other topics, some conditions will provide an entirely new function. our topic is all about ERROR FUNCTIONS in Advance Engineering Mathematics.

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Evaluate the piecewise function at the given value of the independent variable. x²+5 X-7 h(x) = X-5 if x #7 if x = 7 OA. -2 B. 12 C. Undefined D. 2 ;h(7) 31 Clear all pyright © 20ZZ Pearson Education Inc. All rights reserved. I Terms of Use | Privacy Policy 9 ♫ tv
Find a formula for the function whose graph is below.
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2. In each item below, you are given sets A and B, and a formula for a (non?)function f: A → B. In each case, determine whether or not the formula gives a well-defined function. Fully justify your answers. (a) A = Q = B, f(r) = a root in B of the polynomial X² - r (b) A = C = B, f(2)= a root in B of the polynomial X² – z (c) A = P(R) - {0}¹, B = R₁ ƒ(E) = the smallest element of E (d) A = P(R), B = R, ƒ(E) = the smallest element of E if E admits a smallest ele- ment, and f(E)= 0 otherwise A function f : A → B is injective (or one-to-one) if it satisfies the following condition: for all a₁, a2 € A, if f(a₁) = f(a₂), then a₁ = a₂; f is surjective (or onto) if f(A) = B, or, more explicitly, if for each b E B there exists a € A such that f(a) = b; f is bijective if f is both injective and surjective. Here are some examples. • The squaring function f : R → R given by f(x) = x² is not injective because f(-1) = 1 = f(1); f also fails to be surjective because -1 is not in the range of f. The…