From a known point V (vertex), the tangent lines of a compound curve are drawn - having azimuths 300° (forward tangent) and bearing N 04° E (back tangent), respectively. A common tangent line CD intersects the two tangent lines at bearing S 34° E. Stationing of the vertex of the compound curve is 16+ 464.35 and the distance from point D to the vertex of the compound curve is 137.6 m. If the external distance of the curve passing through the PC is 1.42 times the external distance of the simple curve that passes through the PT, solve for the following. a. Radius of the curve that passes through the PC b. Radius of the curve that passes through the PT c. Stationing of the PT

From a known point V (vertex), the tangent lines of a compound curve are drawn - having azimuths 300° (forward tangent) and bearing N 04° E (back tangent), respectively. A common tangent line CD intersects the two tangent lines at bearing S 34° E. Stationing of the vertex of the compound curve is 16+ 464.35 and the distance from point D to the vertex of the compound curve is 137.6 m. If the external distance of the curve passing through the PC is 1.42 times the external distance of the simple curve that passes through the PT, solve for the following. a. Radius of the curve that passes through the PC b. Radius of the curve that passes through the PT c. Stationing of the PT

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Dimensional homogeneity

The term dimensional homogeneity means that in an equation, the dimensions of each term on both sides are equal, which means the dimensions of the left-hand side (LHS) of an equation are similar to the dimensions of the right-hand side (RHS). For a dimensionally homogeneous equation, the powers of fundamental dimensions will be identical on both sides of the equation.

Question

Please write the given and formula that be used. Draw the figure. Box final answer.

From a known point V (vertex), the tangent lines of a compound curve are drawn -
having azimuths 300° (forward tangent) and bearing N 04° E (back tangent),
respectively. A common tangent line CD intersects the two tangent lines at bearing S
34° E. Stationing of the vertex of the compound curve is 16+ 464.35 and the distance
from point D to the vertex of the compound curve is 137.6 m. If the external distance of
the curve passing through the PC is 1.42 times the external distance of the simple curve
that passes through the PT, solve for the following.
a. Radius of the curve that passes through the PC
Radius of the curve that passes through the PT
c. Stationing of the PT
b.

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