Fresh Donuts! A donut company says that their donuts remain fresh for over 2 days on average. A donutwatchdog organization samples 15 donuts and finds that on average they remain fresh 2.1 days with astandard deviation of 0.8 days. Evaluate the company's claim using a hypothesis test. Use a 5% level ofsignificance. Assume that donut freshness follows a normal distribution.(a) Write the hypotheses for the test:O Ho: H = 2.1Hại p < 2.1OH,: µ = 2Ha: p > 2OH,: µ = 2.1Hạ: p = 2.1O H,: H = 2Hạ: p< 2O H,: µ = 2Hạ: p = 2OH;: H = 2.1Ha: p > 2.1(b) Compute the p-value for the test:p =|(round to three sig figs)(c) What is the final conclusion?O There is sufficient evidence to reject the company's claim.O There is not sufficient evidence to reject the company's claim.O There is not sufficient evidence to support the company's claim.O There is sufficient evidence to support the company's claim.Question Help: M Message instructor D Post to forumSubmit All PartsJump to Answer

Hypothesized Population Mean (\mu)(μ) = 22 Sample Standard Deviation (s)(s) = 0.80.8 Sample…

Answered: Fresh Donuts! A donut company says that…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance. one-tailed or two-tailed test: State the hypotheses: df= tα or t value for the critical region = sM = t (test statistic)= Decision:
The average student-loan debt is reported to be $25,235. A student believes that the student-loan debt is higher in her area. She takes a random sample of 100 college students in her area and determines the mean student-loan debt is $27,524 and the standard deviation is $6,000. Is there sufficient evidence to support the student's claim at a 5% significance level? Test the claim: Determine the null and alternative hypotheses. Enter correct symbol and value.�0: �=��: � Determine the test statistic. Round to two decimals.�= Find the �-value. Round to 4 decimals.�-value =
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purses Researchers conducted an experiment to test the effects of alcohol. Erors were recorded in a test of visual and motor skills for a treatment group of 21 people who drank ethanol and another group of 21 people given a placebo. The errors for the treatment group have a standard deviation of 2.10, and the errors for the placebo group have a standard deviation of 0.71. Use a 0.05 significance level to test the claim that the treatment group has errors that vary significantly more than the errors of the placebo group. Assume that the two populations are normally distributed. se Hom bus What are the null and alternative hypotheses? ndar O A. Ho: o =0 O B. Ho: of +o? ntation OC. Ho o =0 OD. Hoi o? =o} book puncem Identify the test statistic. (Round to two decimal places as needed.) gnments Use technology to identify the P-value. dy Plan (Round to three decimal places as needed.) debook What is the conclusion for this hypothesis test? O A. Reject Ho. There is sufficient evidence to…
A researcher is interested in seeing if the average income of rural families is greater than that of urban families. To see if his claim is correct he randomly selects 12 families from a rural area and finds that they have an average income of $67255 with a standard deviation of $570. He then selects 22 families from a urban area and finds that they have an average income of $66577 with a standard deviation of $939. Perform a hypothesis test using a significance level of 0.10 to help him decide. Let the rural families be sample 1 and the urban families be sample 2. The correct hypotheses are: Ho: 1 ≤ 2 HA:μι > μ2(claim) Ο Ηο: μι 2 μ2 HAM12(claim) O Ho: 1 = ₂ HA: 12(claim) Since the level of significance is 0.10 the critical value is 1.309 (round to 3 places) The test statistic is: The p-value is: (round to 3 places)
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A researcher is interested in seeing if the average income of rural families is greater than that of urban families. To see if his claim is correct he randomly selects 12 families from a rural area and finds that they have an average income of $67255 with a standard deviation of $570. He then selects 22 families from a urban area and finds that they have an average income of $66577 with a standard deviation of $939. Perform a hypothesis test using a significance level of 0.10 to help him decide. Let the rural families be sample 1 and the urban families be sample 2. The correct hypotheses are: Ho: 1 ≤ 2 HA:μι > μ2(claim) Ο Ηο: μι 2 μ2 HAM12(claim) O Ho: 1 = ₂ HA: 12(claim) Since the level of significance is 0.10 the critical value is 1.309 (round to 3 places) The test statistic is: The p-value is: (round to 3 places)
Fresh Donuts! A donut company claims that their donuts remain fresh for more than 2 days on average. A donut watchdog organization samples 16 donuts and finds that on average they remain fresh 2.8 days with a standard deviation of 0.9 days. Evaluate the company's claim using a hypothesis test. Use a 5% level of significance. Assume that donut freshness follows a normal distribution.(a) Write the hypotheses for the test:(b) Compute the p-value for the test:
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An article in the San Jose Mercury News stated that students in the California state university system take 6 years, on average, to finish their undergraduate degrees. A freshman student believes that the mean time is less and conducts a survey of 53 students. The student obtains a sample mean of 4.1 with a sample standard deviation of 1.9. Is there sufficient evidence to support the student's claim at an �=0.1 significance level? Test the claim: Determine the null and alternative hypotheses. Enter correct symbol and value.�0: �=Incorrect��: � Correct< Incorrect Determine the test statistic. Round to four decimal places.�=Incorrect Find the �-value. Round to 4 decimals.

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