Freezing point lauric acid = 44.5 degrees C  Freezing point solution = 40.7 degrees C Mass of unknown solid = 0.4156g Mass of lauric acid = 3.936g  The freezing point depression constant of lauric acid is 4.40C/molal Calculate  a) Freezing point depression b) Molality of unknown (m) c) Moles of unknown (mol) d) Molar Mass of unknown

Q: Match the following aqueous solutions with the appropriate letter from the column on the right. 1 1.…

A: Depression in freezing point of solution = Freezing point of solvent – freezing point of solution…

Q: Match the following aqueous solutions with the appropriate letter from the column on the right. 1.…

A: The depression in Freezing point can be given as follows: where ΔTf: Depression in freezing point…

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A: Step 1:Step 2:Step 3:

Q: B. Calculate the molality of a water solution if the freezing point is: 6. -9.3°C 7. -27.9°C

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Q: you

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Q: Calculate the molality of a solution formed by adding 9.40 g NH4Cl to 16.3 g of water. molality:

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Q: SUBJECT : GENERAL CHEMISTRY TOPIC : COLLIGATIVE PROPERTIES

A: Note: Since you have asked multiple questions, we will solve the first question for you. If you want…

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