nalyze the free-body diagram, given the coefficients of static and kinetic friction.petermine whether the block will slide and the net force on the system.2 3friction is not shown, but must be included in calculations!statickineticHs = 0.25Hk = 0.2N=fs,maxfr =frictionW2 [N]slide?friction [N]|Fnee| [N]directionWa= 102N40W2WN = 200N80(see table)W; = 225N120160200cannot be determinedcheck answers| Rain to stopA ĝ a 4 ¢ACCTchVE = att-3:20近

Name: nalyze the free-body diagram, given the coefficients of static and ki
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Description: nalyze the free-body diagram, given the coefficients of static and kinetic friction.petermine whether the block will slide and the net force on the system.2 3friction is not shown, but must be included in calculations!statickineticHs = 0.25Hk = 0.2N

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nalyze the free-body diagram, given the coefficients of static and kinetic friction.
petermine whether the block will slide and the net force on the system.
2 3
friction is not shown, but must be included in calculations!
static
kinetic
Hs = 0.25
Hk = 0.2
N=
fs,max
fr =
friction
W2 [N]
slide?
friction [N]
|Fnee| [N]
direction
Wa= 102N
40
W2
WN = 200N
80
(see table)
W; = 225N
120
160
200
cannot be determined
check answers
| Rain to stopA ĝ a 4 ¢
ACC
Tch
VE = at
t-3:20
近

Expert Solution

Step 1

We have given the free body diagram of the system as shown above n the figure

Here we have given that let the angle of incline of the plane is $θ$

then normal force is given as

$mgcos (θ) = 200 N we know that mg = 225 N So 225 \cos (θ) = 200 N \cos (θ) = \frac{200}{225} θ = \cos^{- 1} (\frac{200}{225}) θ = 27.26 \approx 27.3 θ = 27.3 °$

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