**Ordinate and Area for a Normal Error Curve**The formula for the z-score is:\[ z = (x - \mu)/\sigma \]*Note: The area refers to the area between z = 0 and z = the table value.*Below is a table displaying the values of z, the corresponding ordinate \( y \), and the area under the normal curve between z = 0 and the table value of z:| z | y | Area ||-----|--------|--------|| 0.0 | 0.3989 | 0.0000 || 0.1 | 0.3970 | 0.0398 || 0.2 | 0.3910 | 0.0793 || 0.3 | 0.3814 | 0.1179 || 0.4 | 0.3683 | 0.1554 || 0.5 | 0.3521 | 0.1915 || 0.6 | 0.3332 | 0.2258 || 0.7 | 0.3123 | 0.2580 || 0.8 | 0.2897 | 0.2881 || 0.9 | 0.2661 | 0.3159 || 1.0 | 0.2420 | 0.3413 || 1.1 | 0.2179 | 0.3643 || 1.2 | 0.1942 | 0.3849 || 1.3 | 0.1714 | 0.4032 || 1.4 | 0.1497 | 0.4192 || 1.5 | 0.1295 | 0.4332 || 1.6 | 0.1109 | 0.4452 || 1.7 | 0.0941 | 0.4554 || 1.8 | 0.0790 | 0.4641 || 1.9 | 0.0656 | 0.4713 || 2.0 | 0.0540 | 0.4773 || 2.1 | 0.0440 | 0.482 A clinic took temperature readings of 250 flu patients over a weekend and discovered the temperature distribution to be Gaussian, with a mean of 102.00 °F and a standard deviation of 0.8700 °F.Use this normal error curve area table to calculate each value.What is the fraction of patients expected to have a fever greater than 103.91 °F?fraction above 103.91 °F: [ ]What is the fraction of patients expected to have a temperature between 101.30 °F and 102.96 °F?fraction between 101.30 °F and 102.96 °F: [ ]

Let X be the random variable that temperature.Given that,Population mean Population standard…

Answered: fraction above 103.91 °F: What is the…

fraction above 103.91 °F: What is the fraction of patients expected to have a temperature between 101.30 °F and 102.96 °F? fraction between 101 30 °F and 102 96 °F-

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

100%

**Ordinate and Area for a Normal Error Curve**

The formula for the z-score is:

\[ z = (x - \mu)/\sigma \]

*Note: The area refers to the area between z = 0 and z = the table value.*

Below is a table displaying the values of z, the corresponding ordinate \( y \), and the area under the normal curve between z = 0 and the table value of z:

| z | y | Area |
|-----|--------|--------|
| 0.0 | 0.3989 | 0.0000 |
| 0.1 | 0.3970 | 0.0398 |
| 0.2 | 0.3910 | 0.0793 |
| 0.3 | 0.3814 | 0.1179 |
| 0.4 | 0.3683 | 0.1554 |
| 0.5 | 0.3521 | 0.1915 |
| 0.6 | 0.3332 | 0.2258 |
| 0.7 | 0.3123 | 0.2580 |
| 0.8 | 0.2897 | 0.2881 |
| 0.9 | 0.2661 | 0.3159 |
| 1.0 | 0.2420 | 0.3413 |
| 1.1 | 0.2179 | 0.3643 |
| 1.2 | 0.1942 | 0.3849 |
| 1.3 | 0.1714 | 0.4032 |
| 1.4 | 0.1497 | 0.4192 |
| 1.5 | 0.1295 | 0.4332 |
| 1.6 | 0.1109 | 0.4452 |
| 1.7 | 0.0941 | 0.4554 |
| 1.8 | 0.0790 | 0.4641 |
| 1.9 | 0.0656 | 0.4713 |
| 2.0 | 0.0540 | 0.4773 |
| 2.1 | 0.0440 | 0.482

A clinic took temperature readings of 250 flu patients over a weekend and discovered the temperature distribution to be Gaussian, with a mean of 102.00 °F and a standard deviation of 0.8700 °F.

Use this normal error curve area table to calculate each value.

What is the fraction of patients expected to have a fever greater than 103.91 °F?

fraction above 103.91 °F: [ ]

What is the fraction of patients expected to have a temperature between 101.30 °F and 102.96 °F?

fraction between 101.30 °F and 102.96 °F: [ ]

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