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Four students each made a statement about the equation of a line in R² given in vector form, 7 = (-3,5) + t(2,-3). Which students is/are correct? Justify your answer. i. Eleven: The equation of this line in scalar form is 2x + 3y - 1 = 0 ii. Lucas: A line L, that is parallel to the given line is as follows: (x = 1+ 2.5t L: y=8-3.75t iii. Finn: A vector that is perpendicular to the given line is v = (9,-4) iv. Dustin: Two points on this line are: (-1,2) and (0,0.5)

Four students each made a statement about the equation of a line in R² given in vector form, 7 = (-3,5) + t(2,-3). Which students is/are correct? Justify your answer. i. Eleven: The equation of this line in scalar form is 2x + 3y - 1 = 0 ii. Lucas: A line L, that is parallel to the given line is as follows: (x = 1+ 2.5t L: y=8-3.75t iii. Finn: A vector that is perpendicular to the given line is v = (9,-4) iv. Dustin: Two points on this line are: (-1,2) and (0,0.5)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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2. Four students each made a statement about the equation of a line in R² given in vector form, 7 = (-3,5) + t(2,-3). Which students is/are correct? Justify your answer. i. Eleven: The equation of this line in scalar form is 2x + 3y - 1 = 0 ii. Lucas: A line L, that is parallel to the given line is as follows: (x = 1 + 2.5t L:y=8-3.75t iii. Finn: A vector that is perpendicular to the given line is v = (9,-4) iv. Dustin: Two points on this line are: (-1,2) and (0, 0.5)
Transcribed Image Text:2. Four students each made a statement about the equation of a line in R² given in vector form, 7 = (-3,5) + t(2,-3). Which students is/are correct? Justify your answer. i. Eleven: The equation of this line in scalar form is 2x + 3y - 1 = 0 ii. Lucas: A line L, that is parallel to the given line is as follows: (x = 1 + 2.5t L:y=8-3.75t iii. Finn: A vector that is perpendicular to the given line is v = (9,-4) iv. Dustin: Two points on this line are: (-1,2) and (0, 0.5)
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