Four resistors of R1 = R, R2 = 3 R, R3 = 5 R, and R4 - R/3 (R is the resistance of the first resistor and the others are related to the first resistor by some factor) are connected purely in series to a 57 volt battery. 33 Coulombs of charge passes through a point of the wire in 4 seconds. What is the power dissipated by resistor. Re, in Watts?

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Four resistors of R, = R, R2 = 3 R, R = 5 R, and Ra = R/3 (R is the resistance of the first
resistor and the others are related to the first resistor by some factor) are connected
purely in series to a 57 volt battery. 33 Coulombs of charge passes through a point of
the wire in 4 seconds. What is the power dissipated by resistor. Ra, in Watts?
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Expert Solution
Step 1

R1 = RR2 = 3RR3 = 5RR4 = R/3V = 57 V

For resistors in series,

Rs = R1 + R2 + R3 + R4Rs = R + 3R + 5R + R3Rs = 9R + R3Rs = 9.34R

 

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