Four point charges are equally separated by 1.00 m in air as shown. If q1 = 3.0 nC, q2 = -4.0 nC, q3 = 2.0 nC, and q4 = -5.0 nC, what is the electric field at a point halfway between q2 and q3?
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Four point charges are equally separated by 1.00 m in air as shown. If q1 = 3.0 nC, q2 = -4.0 nC, q3 = 2.0 nC, and q4 = -5.0 nC, what is the electric field at a point halfway between q2 and q3?
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- Two blocks are released from rest on either side of a frictionless half-pipe (see the Figure below). Block B is less massive than block A. The height HB from which block B is released is less than HA, the height from which block A is released. The blocks collide elastically on the flat section. HA B HB 1) After the collision, which is correct? Block A rises to a height greater than HA and block B rises to a height less than HB. Block A rises to a height less than HA and block B rises to a height greater than HB. Block A rises to height HA and block B rises to height HB. Block A rises to height HB and block B rises to height HA. The heights to which the blocks rise depends on where along the flat section they collide. SubmitTwo charges of q1=+ 3.0nC and q2=- 7.0 nC are separated by a distance of 50 cm. What is the electric field strength at a point that is 20cm from q1 and 30 cm from q2? The point lies between q1 and q2.Three point charges are located on a circular arc as shown in the figure below. (Let r = 4.16 cm. Assume that the +x-axis is to the right and the +y-axis is up along the page.) +3.00 nC -2.00 nC 30.0° P 30.0° +3.00 nC (a) What is the total electric field at P, the center of the arc? magnitude 16622 v N/C direction to the right (b) Find the electric force that would be exerted on a -5.21 nC point charge placed at P. magnitude x N downwards x 3.9*10**-5 direction
- Four point charges are equally separated by 1.00 m in air as shown. If q1 = 3.0 nC, q2 = -4.0 nC, q3 = 2.0 nC, and q4 = -5.0 nC, what is the electric field at a point halfway between q2 and q3?Three charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q = 2.00 μC, and L = 0.550 m.) q: 7.00 με y 60.0° L 9 - x -4.00 μC (a) Calculate the electric field at the position of charge q due to the 7.00-μC and -4.00-μC charges. Once you calculate the magnitude of the field contribution from each charge you need to add these as vectors. KN/C 1 + Does the -4.00-μC charge contribute to the y component of the field at the origin? KN/C ĵ (b) Use your answer to part (a) to determine the force on charge q. If you know the electric field at a particular point, how do you find the force that acts on a charge at that point? mN I + Check units carefully. Note that the field in part (a) is given in kN/J and the force in this part is given in mN. mNĵ xTwo parallel plates 11 cm on a side are given equal and opposite charges of magnitude 5.2×10-⁹ C. The plates are 1.5 mm apart. What is the electric field at the center of the region between the plates? ×104 N/C E =
- Two test charges are located in the xy plane. Charge q₁ = -3.950 nC and is located at x₁ = 0.00 m, y₁ = 0.7200 m. Charge 92 = 4.600 nC and is located at x2 = 1.100 m, y2 = 0.650 m. Calculate the x and y components, Ex and Ey, respectively, of the electric field Ĕ at the origin, (0, 0). The Coulomb force constant is 1/(4леo) = 8.99 × 10⁹ N.m²/C². Ex = N/C ㄢˋ Ey = = N/CConsider point charge Q₁ positioned in the x-y plane as shown in the figure. y (cm) 90 80 70 60 50 40 30 20 10 0 H Q1 0 10 20 30 40 50 60 70 80 90 x (cm) The point charge has the following value: Q₁ = -35.9 nC. What is the magnitude of the electric field at the position P? 4.360x102 N/C You are correct. Your receipt no. is 159-4863 Ⓒ What is the y-component of the electric field vector at this location? Previous TriesTwo equal positive charges (10 μC) are arranged at the base of an equilateral triangle of sides 20 cm. What is the electric field at the top vertex of the triangle? What is the direction of the electric field?