Answered: Four point charges are at the corners…

Similar questions

Three-point charges are arranged as shown in the figure below. Find the magnitude and direction of the electric force on the particle q = 5.20 nC at the origin. (Let r12 = 0.260 m.) find magnitude and direction counterclockwise from the +x axis
Three point charges are located at the corners of an equilateral triangle as in the figure below. Find the magnitude and direction of the net electric force on the 1.30 µC charge. (Let A = 1.30 µC, B = 6.80 µC, and C = -4.32 µC.) %3D В 0.500 m 60.0° + A C magnitude N direction ° below the +x-axis
Three point charges are arranged as shown in the figure below. Find the magnitude and direction of the electric force on the particle q = 4.90 nC at the origin. (Let r12 = 0.275 m.) magnitude N and direction ° counterclockwise from the +x axis
Three point charges are located at the corners of an equilateral triangle as shown. Each leg of 9₁ 1 = 4.88 the triangle has a length of 1.64 meters. And the charges have values as follows. Q microcoulombs, 28.03 microcoulombs, and 3 = -6.33 microcoulombs. f Calculate the net electric force (both magnitude and direction) exerted on 1. Magnitude? 3.98E-1N Direction? 237.95deg Submit Answer Incorrect. Tries 19/99 Previous Tries 2.2. Calculate the net electric force (both magnitude and direction) exerted on Magnitude? Submit Answer Tries 0/99 Direction? Q3. Calculate the net electric force (both magnitude and direction) exerted on Direction? Magnitude? Submit Answer Tries 0/99
Two point charges are situated in a cartesian coordinate system as follow; 91-9.6 x 10 C @ the coordinates (-0.49, 0.92) m 92= -3.4 x 106 C @ the coordinates (0.74, 0.45) m What is the direction of the net electric field at the origin (0, 0)? Answer this as an angle measured in degrees relative to the +x direction. Let answers in the first 3 quadrants be positive and negative in the 4th quadrant.
Two charges, q1=-0.3mC and q2=--1.94mC are placed 12.02m apart from one another (mC stand for "milli-Coulomb"). What is the the electric force that q2 experiences due to the presence of q1? Note, if the force direction is "to the left" be sure to include a negative sign. If the direction of the force is "to the right", the force should be positive in sign.
Three point charges are fixed as shown in the figure. You are given that q-5 uC and a = 0.3 m. Find the magnitude of the net electric force (in N) on the charge located at the origin. b- +g b-
Three charges are at the corners of an equilateral triangle, as shown in the figure below. Calculate the electric field at a point midway between the two charges on the x-axis. (Let q1 = 2.50 ?C,q2 = 6.00 ?C,and q3 = −2.50 ?C.)
Given the arrangement of charged particles in the figure below, find the net electrostatic force on the 9₁ = 5.15-μC charged particle. (Assume q2 = 16.33 µC and 93 = -19.12 μC. Express your answer in vector form.) 7 = X N 91 (-2.00 cm, 0) 93 (1.00 cm, 1.00 cm) 92 (0, -1.00 cm)
Either all parts or none, asap plxxx
Questions 8-10 refer to the figure below. 91 а 92 а а 94 а 93 8. Four charges q1 = of the square have a length a. In terms of ke, Q, and a calculate the electric force acting on q1 due to q2, 93, and +Q, q2 = +Q, 93 = –Q, and q4 = -Q are in the corners of a square. The sides 4. A. ke (-0.65ây – 1.35g) C. kQ (0.65 + 1.35ŷ) В. К(-1.352 — 0.659) D. k (1.35â + 0.65ý) a2 a2 9. Four charges q1 = +Q, q2 = +Q, q3 = -Q, and q4 = -Q are in the corners of a square. The sides of the square have a length a. In terms of ke, Q, and a calculate the electric force acting on 2 due to q1, 93, and q4. A. k (0.65â – 1.35ŷ) C. E(-0.65£ + 1.35ŷ) D. g(-1,35 + 0.65ý) Q² B. k (1.35â – 0.65ý) 10. Four charges q1 = +Q, q2 = +Q, q3 = -Q, and q4 = -Q are in the corners of a square. The sides of the square have a length a. In terms of ke, Q, and a calculate the electric force acting on q3 due to q1, 92, and q4. A. k(-0.65â – 1.35g) B. k(-1.35â – 0.65ŷ) D. ke (1.35€ + 0.65ŷ) С. К (0.65 + 1.35)
I got the answer wrongly. Would anyone be able to explain the reason behind this??

SEE MORE QUESTIONS

F	=
direction		° counterclockwise from the +x-axis