The image contains a problem related to probability and statistics, specifically about analyzing data from a study on teenagers obtaining driver's licenses.**Text Transcription:**A study performed by a university's transportation research institute stated that 24% of U.S. teenagers between the ages of 17 and 19 did not possess a driver's license. A random sample of 125, 17- to 19-year-old teenagers was selected. Complete parts a through d.a. What is the probability that 45 or fewer teenagers of this sample had not obtained a driver's license? (Round to four decimal places as needed.)b. What is the probability that 50 or more teenagers of this sample had not obtained a driver's license? (Round to four decimal places as needed.)c. Suppose that 27 teenagers from this sample had not obtained a driver's license. Does this result support the findings reported by the university's transportation research institute? Complete the statement. (Round to four decimal places as needed.)The result (does/does not) support the claim because the probability of finding a sample proportion at least as extreme as the one found is (which is less than or equal to 0.05/which is greater than 0.05).d. The results do support the claim because the probability of finding a sample proportion at least as extreme as the one found is (which is less than or equal to 0.05/which is greater than 0.05).Options:- O. A- O. B- O. C- O. D**Explanation:**This exercise involves calculating probabilities using statistical methods in order to analyze whether the sample data supports a given claim. The exercise focuses on understanding probabilities in a sample proportion context and interpreting statistical results in real-world scenarios. There's no graph or diagram to explain in this image.

Hello! As you have posted more than 3 sub parts, we are answering the first 3 sub-parts. In case you require the unanswered parts also, kindly re-post that parts separately. Given information: Sample size is, n=125 Population proportion is, p=0.29 a) The probability that 45 or fewer teenagers of the sample had not obtained a driver's license is, PX≤45=PX≤45+0.5 For normal approximation, continuity correction=0.5 =PX-μσ≤45.5-μσ =Pz≤45.5-npnp(1-p) =Pz≤45.5-125*0.29125*0.29*(!-0.29) =Pz≤1.8233 =0.9659, from the excel function, =NORM.DIST(1.8233,0,1,TRUE) b) The probability that 50 or more teenagers of the sample had not obtained a driver's license is, PX≥50=PX≥50-0.5 For normal approximation, continuity correction=0.5 =PX-μσ≥49.5-μσ =1-Pz≤49.5-npnp(1-p) =1-Pz≤45.5-125*0.29125*0.29*(!-0.29) =1-Pz≤2.6118 =0.0045, from the excel function, =1-NORM.DIST(2.6118,0,1,TRUE)c) The probability that the teenagers of the sample between 35 and 40 had not obtained a driver's license is, P35≤X≤≤40=P35-0.5≤X≤40+0.5 For normal approximation, continuity correction=0.5 =P34.5-μσ≤X-μσ≤40.5-μσ =1-P34.5-npnp(1-p)≤z≤40.5-npnp(1-p) =Pz≤40.5-125*0.29125*0.29*(!-0.29)-Pz≤34.5-125*0.29125*0.29*(!-0.29) =Pz≤0.8377-Pz≤-0.345 =0.4339, from the excel function, ==NORM.DIST(0.8377,0,1,TRUE)-NORM.DIST(-0.345,0,1,TRUE)