### Practice ExercisesIn this chapter, you will learn to determine the formula mass of a substance and the number of moles of a substance. You will practice writing and balancing chemical equations and use these equations to determine the amounts of substances that react and are produced in chemical reactions.#### Formula MassThe **formula mass** (Sec. 6.1) of a compound is the sum of the atomic masses, expressed in atomic mass units (amu), of the atoms in the chemical formula of the substance. Calculate the formula mass, rounded to the hundredths place, for each of the compounds below. Atomic masses are given on the inside front cover of your textbook.| Formula | Calculations with atomic masses | Formula mass ||-----------|-----------------------------------------------------|--------------|| KBr | K = 39 + Br = 80 | 119.00 amu || CaCl₂ | Ca = 40 + Cl₂ = 35 | 75 amu || Na₂CO₃ | Na₂ = 46 + CO₃ = 60 | 146.00 amu || (NH₄)₃PO₄ | (No calculation provided) | (No mass given) |#### The MoleThe **mole** (Sec. 6.2 and 6.3) is a useful unit for counting numbers of atoms and molecules. The number of particles in a mole is 6.02 x 10²³, which is known as **Avogadro's number** (Sec. 6.2). Use the definition of Avogadro's number as a conversion factor in the calculations below:| Moles | Quantity with conversion factor | Number of atoms ||------------|---------------------------------|------------------|| 1.00 mole He atoms | | || 2.60 moles Na atoms| | || 0.316 mole Ar atoms| | |#### The Molar MassThe mass of 1 mole, the **molar mass** (Sec. 6.3), of any substance is its formula mass (amu) expressed in grams. Answer the questions below to check your understanding of molar mass.1. What is the mass in amu of one carbon atom? _______________2. What is the molar mass of carbon? _______________3. **Chemical Calculations: Formula Masses, Moles, and Chemical Equations - Chapter 6****Chapter Overview**Calculation of the ratios and masses of the substances involved in chemical reactions is very important in many chemical processes. Central to these calculations is the concept of the mole, a convenient counting unit for atoms and molecules.In this chapter, you will learn to determine the formula mass of a substance and the number of moles of a substance. You will practice writing and balancing chemical equations, and you will learn to use these equations in determining the amounts of substances that react and are produced in chemical reactions.**Practice Exercises****6.1 The Formula Mass** (Sec. 6.1) of a compound is the sum of the atomic masses, expressed in atomic mass units (amu), of the atoms in the chemical formula of the substance. Calculate the formula mass, rounded to the hundredths place, for each of the compounds below. Atomic masses are given on the inside front cover of your textbook.| Formula | Calculations with atomic masses | Formula mass ||-----------|----------------------------------------|--------------|| KBr | K = 39 + Br = 80 | 119.00 amu || CaCl₂ | Ca = 40 | 75.00 amu || | Cl₂ = 35 x 2 = 70 | || Na₂CO₃ | Na₂ = 46 | 146.00 amu || | C = 12, O₃ = 48 | || (NH₄)₃PO₄ | | |**6.2 The Mole**(Sec. 6.2 and 6.3) is a useful unit for counting numbers of atoms and molecules. The number of particles in a mole is 6.02 x 10²³, which is known as Avogadro’s number (Sec. 6.2). Use the definition of Avogadro’s number as a conversion factor in the calculations below:| Moles | Quantity with conversion factor | Number of atoms ||----------------|---------------------------------|-----------------|| 1.00 mole He atoms | | || 2.60 moles Na atoms | | || 0.316 mole Ar atoms | | |**6.3 The Mass

"Since you have asked multiple questions, we will solve the first question for you. If you want any specific question to be solved then please specify the question number or post only that question.” Formula Calculations with atomic masses Formula Mass KBr K=39.09 amu , Br= 79.90 amu KBr= 39.09 + 79.90 =118.99 amu 119 amu CaCl2 Ca=40.07 amu ,Cl= 35.5 amu CaCl2= Ca+ 2x Cl =40.07 + (2x 35.5) =111amu 111 amu Na2CO3 Na=22.98 amu , C=12.01, O=15.99 amu Na2CO3= 2 x Na + C +3 x O =(2 x 22.98) + 12.01 + (3 x 15.99) =45.96 + 12.01 +47.97 =105.94 amu 106 amu (NH4)3PO4 N=14.00 amu , H=1.00 amu , P=30.97 amu , O=15.99 amu (NH4)3PO4 = 3 x N +12 x H + P + 4 x O = (3 x 14.00) +(12 x 1.00)+ (1 x30.97)+ (4x 15.99) = 42 + 12 + 30.97 + 63.96 = 148.93 amu 149 amu

Answered: Formula Calculations with atomic masses…

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Chemistry

Formula Calculations with atomic masses Formula mass 119.00amu 75amul 146.00am K= 39 + Br=80 KBr Ca-40 CLこ35 CaCl2 Naz=40 CO3 = Na,CO, (NH),PO. The mole (Sec 6 2 and 6 2) in n voeful ueit fe

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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