Force per Unit Length on a Half Part of an Infinite Charged CylinderConsider an infinite charged cylinder with radius (r) in a vacuum. Thecharge is distributed uniformly inside the cylinder. The cylinder moves withvelocity (7) parallel to its symmetrical axis. If the value of the electrical fieldon the surface is (Eo), find the force per unit length (f) applied by itself ona half part of it! (Hint: Use the Maxwell's Stress Tensor)E(R) = EoRFigure 1: A moving infinite charged cylinderFigure 2: Force per unit length applied on a half part of the cylinder

Given: The velocity of the cylinder along x-axis is v→ The Electric field at the surface of the…

Answered: Force per Length on a Hal art of an…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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A particle with a charge 1x10-12C and a momentum 3.1x10-15 kg-m/s follows a circular path in a plane which a magnetic field of 2.5 T is directed perpendicular to. What is the radius of the particle's path? A) 1.24 m B) 1.24 cm C) 1.24 um D) 1.24 nm E) 1.24 mm
an infinite sheet (y-2) carries a uniform charge of p.-1pc/m² then the electric flux density at (100,5,1) is Select one: a. b. zero C. 5uc/m²) d. afuc/m²)
A charged particle with speed v = 2 × 105 m/s enters a uniform magnetic field of B = 1.7 T. The velocity of the particle makes an angle of T/3 rad with the magnetic field. Mass and charge of the particle are m = 2.5 x 10-27 kg and q = 8 x 10-19 C, respectively. B Find the pitch of the helical path taken by the particle in ĮPitch units of millimeters. Answer: alea
1. A vertical semicircular area of diameter d = 150 cm is submerged in water and has its diameter in a liquid surface Determine (a) total force acting on one side and (b) its location from the liquid surface.
Q.3: Explain TWO out of three from the following: 1- A balloon clings to a wall after it is negatively charged by rubbing. (a) Does that occur because the wall is positively charged? (b) Why does the balloon eventually fall? 2- Describe the equipotential surfaces for (a) an infinite line of charge and (b) a uniformly charged sphere. 3- How can the motion of a moving charged particle be used to distinguish between a magnetic field and an electric field? Give a specific example to justify your argument?
Consider a charge Q=20 mC at the center of a coordinate system. Consider (1) the flux 41 through the surface of a sphere with radius R1= 1 cm and with its center at the center of the coordinate system 2) the flux 42 through the surface of a sphere at (0,0,-10) cm and with a adius R2=7cm. Identify the correct answer: Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a 41= 42 41=0, 42>0 41>0, 42=0 O<41<42
(1) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L = 7 m and cross-sectional area A = 2.5 mm2 lies along L. The material obeys Ohm's law, and its resistivity varies along the %3D the x-axis between z = 0 and z = rod according to p= po 1 where po L? 2.5 x 10 4N. m. The end of the rod at a = 0 is at a %3D potential Vo = 40 V greater than the end at a = L. A) What is the total resistance, in units of 2, of the rod? Answer: B) What is the current, in units of miliamperes, in the rod? Answer: C) What is the electric potential, in units of Volt, in the rod at z = L/2? Answer:
A particle with charge q = 1.4 C and a long wire carrying current I = 5 A is on the xy-plane at the moment the charge is at point P at distance d = 0.3 cm from the wire and has velocity v = 1.7 m/s in the x-direction. I What is the magnitude of the magnetic force acting on the charge in units of nanonewtons? (µ = 47 x 10 7 T·m/A) 9. Answer:
Wire size and voltage drop The cross-sectional area of wire is measured in circular mils (CM). 1 mil = 1/1000 inch CM = squaring of mil Example 1: Find CM for a piece of wire has a diameter of .008 of an inch. .008 = 8/1000 = 8 mils CM = 8² = 64 Find CM for a piece of wire has a diameter of .008 of an inch. 5. Find Cm for a piece of wire has a diameter of .064 of an inch. 6. Find CM for a Wire has 24 strands of wire and each strand is .012 inches in diameter.
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