For what value of e is a collision perfectly inelastic? a) 1 b) 2 c) 0.5 d) 0
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For what value of e is a collision perfectly inelastic?
a) 1
b) 2
c) 0.5
d) 0

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- Under what condition is the energy lost during a collision maximum? A) e=1.0 B) e = 0.0 C) e=-1.0 D) Collision is non-elastic.Let a mass of 3.0 kg be standing still and a secondmass of 5.0 kg come along and hit it with velocity 4.0 m/s. Supposethe smaller mass moves off with a speed of 5.0 m/s.a) Draw a diagram to describe the situation before the collision.b) What is the velocity of the 5.0 Kg mass after the collision?c) Draw a diagram to describe the situation after the collision.d) What type of collision is it? Support your answer with calculations from Lawof Conservation of Momentum, and Law of Conservation of Energy.A projectile has undergone an elastic one-dimensional collision with an initially stationary target, along an x axis. The figure below is a graph of position versus time for the projectile and target, before and after the collision. (Two line segments are parallel to the time axis.) Which is true about the masses of the projectile and target? 4 O the projectile's mass is greater O the target's mass is greater O the masses are equal
- Enter the % kinetic energy remaining for Collision 1 Enter the % kinetic energy remaining for Collision 2.A 1500 kg object moving at 10 m/s collides with a brick wall and comes to a complete stop. If the collision time is 0.05 what was the average stopping force?m2 m h=7.0m ☐ Figure 1: Diagram for Problem 15 15) During a test investigation, a 40-gram bullet is fired towards a stationary block of 1.0-kg mass causing a perfectly in-elastic collision. After the collision, the block-bullet system slides up a smooth ramp, eventually coming to rest at an elevation of 7.0 meters. Calculate the speed of the bullet. Must show all steps including the equations being used.
- A 700-g wooden block is resting on a frictionless surface when a 50-g bullet traveling at 150 m/s hits it. The bullet is lodged into the wood upon collision and they slide along the surface as a single body. How fast did they slide if we disregard air resistance? A) 10 m/s B) 5.0 m/s C) 7.5 m/s D) 2.5 m/s1a)A 4.50 kg ball rolling north at 5.00 m/s collides with a 2.50 kg ball rolling south at 3.00m/s. If the collision is elastic, set up the equations you would solve to determine how fast is each ball moving after the collision. 1b)If the collision between the two balls in question (1a) instead results in both balls sticking together as one, what will their resulting velocity be?A 1 500 kg car travelling at 25 m/s collides with a 2 500 kg van stopped at a traffic light. As a result of the collision, the two vehicles become entangled. With what initial speed will the entangled mass move off, and is the collision elastic or in elastic? (K:1) SPEED TYPE OF COLLISION A. 9.4 m/s Flastic B. 9.4 m/s Inclastic C. 15 m/s Elastic D. 15 m/s Inclastic Select one: O C D QA B O
- Which of these statements are true? Explain why below: a) If an elastic collision occurs, then the change in total momentum is unpredictable. b) If an elastic collision occurs, then the total momentum is increased by the collision. c) If an elastic collision occurs, then the total momentum is decreased by the collision. d) If an elastic collision occurs, then the total momentum remains essentially unchanged by the collision. Explanation:___________________________________________________________________________________________________________________________________________________________________________________________________________________________________Can you help me with this problem A 0.156 kg glider is moving to the right on a frictionless, horizontal air track with a speed of 0.900 m/sm/s. It has a head-on collision with a 0.291 kg glider that is moving to the left with a speed of 2.15 m/s Suppose the collision is elastic.Find the magnitude of the final velocity of the 0.156 kg glider in m/s. Find the magnitude of the final velocity of the 0.291 kg glider in m/smoving speeds of v₁ = 5.2 m/s m₂ = 2m₁. After the collision Two Particles are and V₂0 and mass mi Of 90° relative to its direction prior to elastic. The collision is is observed to be moving at an angle the Collision, Define a Suitable coordinate system and determine the final velocities (including direction) of each Partille, It also may be useful to remember that cos(20) = Cos²-sin².