For two events, A and B, we have P(A) = 0.85, P(B) = 0.65, and P(AUB) = 0.9. Then, the value for P(BA)

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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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OPTIONS:

a) 0.75

b) cannot be determined due to lack of information

c) 0.71

For two events, A and B, we have
P(A) = 0.85, P(B) = 0.65, and P(AUB) = 0.9. Then, the
value for P(BA)
Transcribed Image Text:For two events, A and B, we have P(A) = 0.85, P(B) = 0.65, and P(AUB) = 0.9. Then, the value for P(BA)
Expert Solution
Step 1

P(A)  = 0.85  P(B) = 0.65  P(AB) = 0.9P(B|A) = ?

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