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For this Supermesh question, I got all of the values for the currents, and how much power was dissipated from the resistor wrong. Can you show me where I went wrong, and how to correct the error?

For this Supermesh question, I got all of the values for the currents, and how much power was dissipated from the resistor wrong. Can you show me where I went wrong, and how to correct the error?

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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For this Supermesh question, I got all of the values for the currents, and how much power was dissipated from the resistor wrong. Can you show me where I went wrong, and how to correct the error?

2I3-you're in mesh 3, se Sust put Example 17: Using the mesh current method, determine Vị, V2, V3, the power of the three sources, and the power dissipated by the 1N resistor in Figure 35. (2Ω 2 A V2 V3 Dov + 10 V 20 -You're in Mesh Zj so justqut I> Figure 35: Circuit for Example 17. ryou're in mesh k, won't subtieet it KVL for mesh 2:/2 (I)– I3) – 6+I2) 2 (I2)– I1) KVL for supermesh (1,3): - 10 + 213 + 2 (I3 – 1,)+ 2 (I – I2) = 0 = 0 - aux. eqn. for supermesh (1, 3): I1 – I3 2 Given I,= 2+ Is 2 Iz-2I3-6+ Iz + 2Jq-2 I,=0 -2 I, +5Iz 2-2Iz :6 -2(2+Is)= H-2I3 5 I2-9I3=110 O 2 (2+J3) = 4+ 2I3 -10 +2 I3 t 2 Iz-2Iz+ 2h - 2I2 =0 4 I3 -4 Iz -2I, :10 4Iz- 4 Iz -(4 +Z I3) 2 I3-4 Iz = ||
Transcribed Image Text:2I3-you're in mesh 3, se Sust put Example 17: Using the mesh current method, determine Vị, V2, V3, the power of the three sources, and the power dissipated by the 1N resistor in Figure 35. (2Ω 2 A V2 V3 Dov + 10 V 20 -You're in Mesh Zj so justqut I> Figure 35: Circuit for Example 17. ryou're in mesh k, won't subtieet it KVL for mesh 2:/2 (I)– I3) – 6+I2) 2 (I2)– I1) KVL for supermesh (1,3): - 10 + 213 + 2 (I3 – 1,)+ 2 (I – I2) = 0 = 0 - aux. eqn. for supermesh (1, 3): I1 – I3 2 Given I,= 2+ Is 2 Iz-2I3-6+ Iz + 2Jq-2 I,=0 -2 I, +5Iz 2-2Iz :6 -2(2+Is)= H-2I3 5 I2-9I3=110 O 2 (2+J3) = 4+ 2I3 -10 +2 I3 t 2 Iz-2Iz+ 2h - 2I2 =0 4 I3 -4 Iz -2I, :10 4Iz- 4 Iz -(4 +Z I3) 2 I3-4 Iz = ||
5 -4 Iz -4 Iz 2 6 A= 10-8 10 4 A, = - 20 -(-24) 44 5 10 :30-(-40) = 70 -4 44 ? 22 A Az I3= 70 > 35 A From given, Il =2+ Iz ue : 2+35 237 Is=37 I should have gotten I,=7A, Iz=6A, Is = 5A, and that He pouer dissopahal fiom He le resisjor is I=36W 3 2
Transcribed Image Text:5 -4 Iz -4 Iz 2 6 A= 10-8 10 4 A, = - 20 -(-24) 44 5 10 :30-(-40) = 70 -4 44 ? 22 A Az I3= 70 > 35 A From given, Il =2+ Iz ue : 2+35 237 Is=37 I should have gotten I,=7A, Iz=6A, Is = 5A, and that He pouer dissopahal fiom He le resisjor is I=36W 3 2
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