For this Supermesh question, I got all of the values for the currents, and how much power was dissipated from the resistor wrong. Can you show me where I went wrong, and how to correct the error?

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For this Supermesh question, I got all of the values for the currents, and how much power was dissipated from the resistor wrong. Can you show me where I went wrong, and how to correct the error?

2I3-you're in mesh 3, se Sust put
Example 17: Using the mesh current method, determine Vị, V2, V3, the power of the three
sources, and the power dissipated by the 1N resistor in Figure 35.
(2Ω
2 A
V2
V3
Dov
+
10 V
20
-You're in Mesh Zj so justqut I>
Figure 35: Circuit for Example 17.
ryou're in mesh k, won't subtieet it
KVL for mesh 2:/2 (I)– I3) – 6+I2) 2 (I2)– I1)
KVL for supermesh (1,3): - 10 + 213 + 2 (I3 – 1,)+ 2 (I – I2) = 0
= 0
-
aux. eqn. for supermesh (1, 3): I1 – I3
2
Given
I,= 2+ Is
2 Iz-2I3-6+ Iz + 2Jq-2 I,=0
-2 I, +5Iz
2-2Iz :6
-2(2+Is)= H-2I3
5 I2-9I3=110 O
2 (2+J3) = 4+ 2I3
-10 +2 I3 t 2 Iz-2Iz+ 2h
- 2I2 =0
4 I3 -4 Iz -2I, :10
4Iz- 4 Iz -(4 +Z I3)
2 I3-4 Iz =
||
Transcribed Image Text:2I3-you're in mesh 3, se Sust put Example 17: Using the mesh current method, determine Vị, V2, V3, the power of the three sources, and the power dissipated by the 1N resistor in Figure 35. (2Ω 2 A V2 V3 Dov + 10 V 20 -You're in Mesh Zj so justqut I> Figure 35: Circuit for Example 17. ryou're in mesh k, won't subtieet it KVL for mesh 2:/2 (I)– I3) – 6+I2) 2 (I2)– I1) KVL for supermesh (1,3): - 10 + 213 + 2 (I3 – 1,)+ 2 (I – I2) = 0 = 0 - aux. eqn. for supermesh (1, 3): I1 – I3 2 Given I,= 2+ Is 2 Iz-2I3-6+ Iz + 2Jq-2 I,=0 -2 I, +5Iz 2-2Iz :6 -2(2+Is)= H-2I3 5 I2-9I3=110 O 2 (2+J3) = 4+ 2I3 -10 +2 I3 t 2 Iz-2Iz+ 2h - 2I2 =0 4 I3 -4 Iz -2I, :10 4Iz- 4 Iz -(4 +Z I3) 2 I3-4 Iz = ||
5
-4
Iz
-4
Iz
2
6
A= 10-8
10 4
A, =
- 20 -(-24)
44
5
10
:30-(-40) = 70
-4
44
? 22 A
Az
I3=
70
> 35 A
From
given, Il =2+ Iz
ue
: 2+35
237
Is=37
I should
have gotten
I,=7A,
Iz=6A, Is = 5A, and
that He
pouer dissopahal fiom He le resisjor is I=36W
3
2
Transcribed Image Text:5 -4 Iz -4 Iz 2 6 A= 10-8 10 4 A, = - 20 -(-24) 44 5 10 :30-(-40) = 70 -4 44 ? 22 A Az I3= 70 > 35 A From given, Il =2+ Iz ue : 2+35 237 Is=37 I should have gotten I,=7A, Iz=6A, Is = 5A, and that He pouer dissopahal fiom He le resisjor is I=36W 3 2
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