For this problem there are 5 variables: x4 – xo. 4 is the most significant (leftmost) variable and co is the least significant (rightmost). This would mean that m25 is x4x32x1x0. Select the simplest SOP equation that represents Σ (do, m2, d5, d7, m8, d10, d13, m15, d16, m18, d21, d23, m24, d26, d29, m31). Again simplest SOP. O X₂X0 + x2x0 O x2 * x0 + x₂ * x1

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Chapter1: Introduction
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Q7 PPLZ, 

For this problem there are 5 variables: \( x_4 - x_0 \). \( x_4 \) is the most significant (leftmost) variable and \( x_0 \) is the least significant (rightmost). This would mean that \( m_{25} \) is \( x_4 x_3 \bar{x_2} \bar{x_1} x_0 \). Select the simplest SOP equation that represents 

\[
\sum (d_0, m_2, d_5, d_7, m_8, d_{10}, d_{13}, m_{15}, d_{16}, m_{18}, d_{21}, d_{23}, m_{24}, d_{26}, d_{29}, m_{31})
\]

Again simplest SOP.

Options:
- \(\circ \quad \bar{x_2} x_0 + x_2 x_0\)
- \(\circ \quad x_2 \ast x_0 + x_2 \ast \bar{x_1}\)
- \(\circ \quad x_2 x_0 + x_3 \bar{x_2} \bar{x_1} \bar{x_0} + x_3 \bar{x_2} x_1 \bar{x_0}\)
- \(\circ \quad x_3 x_2 x_1 x_0 + x_3 x_2 x_1 \bar{x_0}\)
- \(\circ \quad x_2 \ast (\bar{x_1} + x_0)\)
- \(\circ \quad x_2 \bar{x_1} + x_4 x_3 \bar{x_2} x_1 + x_4 x_3 \bar{x_2}\)

A hand-drawn circle highlights the last option.
Transcribed Image Text:For this problem there are 5 variables: \( x_4 - x_0 \). \( x_4 \) is the most significant (leftmost) variable and \( x_0 \) is the least significant (rightmost). This would mean that \( m_{25} \) is \( x_4 x_3 \bar{x_2} \bar{x_1} x_0 \). Select the simplest SOP equation that represents \[ \sum (d_0, m_2, d_5, d_7, m_8, d_{10}, d_{13}, m_{15}, d_{16}, m_{18}, d_{21}, d_{23}, m_{24}, d_{26}, d_{29}, m_{31}) \] Again simplest SOP. Options: - \(\circ \quad \bar{x_2} x_0 + x_2 x_0\) - \(\circ \quad x_2 \ast x_0 + x_2 \ast \bar{x_1}\) - \(\circ \quad x_2 x_0 + x_3 \bar{x_2} \bar{x_1} \bar{x_0} + x_3 \bar{x_2} x_1 \bar{x_0}\) - \(\circ \quad x_3 x_2 x_1 x_0 + x_3 x_2 x_1 \bar{x_0}\) - \(\circ \quad x_2 \ast (\bar{x_1} + x_0)\) - \(\circ \quad x_2 \bar{x_1} + x_4 x_3 \bar{x_2} x_1 + x_4 x_3 \bar{x_2}\) A hand-drawn circle highlights the last option.
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