For this problem, there are 4 variables. 3 is the most significant bit (leftmost) and xo is the least significant (rightmost). This means that m12 is x3 x2 10. Select the equation that represents the simplest SOP form of II(M4, M5, M6, M7, M14). Again simplest SOP!

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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For this problem, there are 4 variables. \( x_3 \) is the most significant bit (leftmost) and \( x_0 \) is the least significant (rightmost). This means that \( m_{12} \) is \( x_3 x_2 \bar{x_1} \bar{x_0} \).

Select the equation that represents the simplest SOP form of \(\prod(M_4, M_5, M_6, M_7, M_{14})\). Again, simplest SOP!

\[
\begin{aligned}
&\bigcirc \quad (x_3 + \bar{x_2}) * (\bar{x_2} + \bar{x_1} + x_0) \\
&\bigcirc \quad (x_2 + x_1) * (\bar{x_3} + \bar{x_1}) * (x_3 + x_2) \\
&\bigcirc \quad \bar{x_2} x_1 + x_3 x_2 \\
&\bigcirc \quad \bar{x_2} + x_3 \bar{x_1} + x_3 x_0 \\
&\bigcirc \quad \bar{x_3} x_2 + x_3 x_2 + x_3 x_0 \\
&\bigcirc \quad (x_3 + \bar{x_2} + x_1) * (x_3 + \bar{x_2} + \bar{x_1}) * (\bar{x_2} + \bar{x_1} + x_0) \\
\end{aligned}
\]

There is a hand-drawn mark indicating an apparent choice with arrows pointing toward the third option: \(\overline{x_2} \, x_1 + x_3 \, x_2\).
Transcribed Image Text:For this problem, there are 4 variables. \( x_3 \) is the most significant bit (leftmost) and \( x_0 \) is the least significant (rightmost). This means that \( m_{12} \) is \( x_3 x_2 \bar{x_1} \bar{x_0} \). Select the equation that represents the simplest SOP form of \(\prod(M_4, M_5, M_6, M_7, M_{14})\). Again, simplest SOP! \[ \begin{aligned} &\bigcirc \quad (x_3 + \bar{x_2}) * (\bar{x_2} + \bar{x_1} + x_0) \\ &\bigcirc \quad (x_2 + x_1) * (\bar{x_3} + \bar{x_1}) * (x_3 + x_2) \\ &\bigcirc \quad \bar{x_2} x_1 + x_3 x_2 \\ &\bigcirc \quad \bar{x_2} + x_3 \bar{x_1} + x_3 x_0 \\ &\bigcirc \quad \bar{x_3} x_2 + x_3 x_2 + x_3 x_0 \\ &\bigcirc \quad (x_3 + \bar{x_2} + x_1) * (x_3 + \bar{x_2} + \bar{x_1}) * (\bar{x_2} + \bar{x_1} + x_0) \\ \end{aligned} \] There is a hand-drawn mark indicating an apparent choice with arrows pointing toward the third option: \(\overline{x_2} \, x_1 + x_3 \, x_2\).
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