For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. In a marketing survey, a random sample of 990 supermarket shoppers revealed that 260 always stock up on an item when they find that item at a real bargain price. (a)  Let p represent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain. Find a point estimate for p. (Enter a number. Round your answer to four decimal places.) ________________ (b)  Find a 95% confidence interval for p. (For each answer, enter a number. Round your answers to three decimal places.) lower limit    _____________  upper limit    _____________

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A: Number of success = x= 3145 n=5804

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A: It is given that n =984 and x =274.

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A: The values are .

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A:

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Q: For this problem, carry at least four digits after the decimal in your calculations. Answers may…

A: Solution: A. Let X be number of supermarket shoppers who always stock up on an item when they find…

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A: Given,n=1020x=270α=1-0.95=0.05α2=0.025Z0.025=1.96    (from Z-table)

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A:

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A: given data, here proportion value is not given so assume that p=q=0.5E= no more than 3%E≤0.03n=?

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A: a)

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A:

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Q: For this problem, carry at least four digits after the decimal in your calculations. Answers may…

A: Solution: Given information: n= 984 Sample size  supermarket shopper. X= 274  stock up

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A:

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.