For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. A random sample of 5805 physicians in Colorado showed that 3332 provided at least some charity care (i.e., treated poor people at no cost). (a) Let p represent the proportion of all Colorado physicians who provide some charity care. Find a point estimate for p. (Round your answer to four decimal places.) (b) Find a 99% confidence interval for p. (Round your answers to three decimal places.) lower limit upper limit Give a brief explanation of the meaning of your answer in the context of this problem. O 99% of the confidence intervals created using this method would include the true proportion of Colorado physicians providing at least some charity care. O 1% of the confidence intervals created using this method would include the true proportion of Colorado physicians providing at least some charity care. O 1% of all confidence intervals would include the true proportion of Colorado physicians providing at least some charity care. O 99% of all confidence intervals would include the true proportion of Colorado physicians providing at least some charity care. (c) Is the normal approximation to the binomial justified in this problem? Explain. O Yes; np > 5 and ng > 5. O No; np < 5 and ng > 5. O Yes; np < 5 and ng < 5. O No; np > 5 and ng < 5.