Answer one of the following1. For the voltage divider circuit, the PNP transistor is used. The components of the circuit are R1= 56 k,R2= 15 kN, the collector resistance is 1.75 kN, and the emitter resistance is 560 2. The Positive poweris 12 V, and the Bpc is 75. Draw this circuit and determine the Ic and VCE.

Given: R1=56KohmR2=15KohmRC=1.75KohmRE=560ohmVE=12vβDC=75

For the voltage divider circuit, the PNP transistor is used. The components of the circuit are R= 56 k2, R2= 15 k2, the collector resistance is 1.75 kN, and the emitter resistance is 560 2. The Positive power is 12 V, and the Bpc is 75. Draw this circuit and determine the Ic and VCE.

For the voltage divider circuit, the PNP transistor is used. The components of the circuit are R= 56 k2, R2= 15 k2, the collector resistance is 1.75 kN, and the emitter resistance is 560 2. The Positive power is 12 V, and the Bpc is 75. Draw this circuit and determine the Ic and VCE.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Differential amplifier

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Question

Answer one of the following
1. For the voltage divider circuit, the PNP transistor is used. The components of the circuit are R1= 56 k,
R2= 15 kN, the collector resistance is 1.75 kN, and the emitter resistance is 560 2. The Positive power
is 12 V, and the Bpc is 75. Draw this circuit and determine the Ic and VCE.

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