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For the values of a for which the linear system 2x + ay + z = น x+2y+2az v x-3y+4z = พ has a unique solution, that solution is given by... Hint: Cramer's rule might be helpful here. ○ This system never has unique solutions. x = y = x = y = x = 8 y = x = (8+ 6a)u (3+ a)v + 2(a² - 2)w - 2a26a13 (2a-4)u+7v+ (1 - 4a)w 2a26a13 -5u+ (6+ a)v+ (4 − a)w 2a26a13 (8+ 6a)u (4a+3)v+ (2a2 - 2)w 2a28a11 (2a-4)u+7v + (1 - 4a)w 2a28a11 −5u+ (6+ a)v+ (4 − a)w 2a28a11 (6+8a)u+ (3+ a)v - 2(a² - 2)w 2a28a11 (a - 4)u+7v+ (1 + 4a)w 2a28a11 u+ (6 − a)v + (4+ a)w 2a28a11

For the values of a for which the linear system 2x + ay + z = น x+2y+2az v x-3y+4z = พ has a unique solution, that solution is given by... Hint: Cramer's rule might be helpful here. ○ This system never has unique solutions. x = y = x = y = x = 8 y = x = (8+ 6a)u (3+ a)v + 2(a² - 2)w - 2a26a13 (2a-4)u+7v+ (1 - 4a)w 2a26a13 -5u+ (6+ a)v+ (4 − a)w 2a26a13 (8+ 6a)u (4a+3)v+ (2a2 - 2)w 2a28a11 (2a-4)u+7v + (1 - 4a)w 2a28a11 −5u+ (6+ a)v+ (4 − a)w 2a28a11 (6+8a)u+ (3+ a)v - 2(a² - 2)w 2a28a11 (a - 4)u+7v+ (1 + 4a)w 2a28a11 u+ (6 − a)v + (4+ a)w 2a28a11

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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For the values of a for which the linear system 2x + ay + z = น x+2y+2az v x-3y+4z = พ has a unique solution, that solution is given by... Hint: Cramer's rule might be helpful here. ○ This system never has unique solutions. x = y = x = y = x = 8 y = x = (8+ 6a)u (3+ a)v + 2(a² - 2)w - 2a26a13 (2a-4)u+7v+ (1 - 4a)w 2a26a13 -5u+ (6+ a)v+ (4 − a)w 2a26a13 (8+ 6a)u (4a+3)v+ (2a2 - 2)w 2a28a11 (2a-4)u+7v + (1 - 4a)w 2a28a11 −5u+ (6+ a)v+ (4 − a)w 2a28a11 (6+8a)u+ (3+ a)v - 2(a² - 2)w 2a28a11 (a - 4)u+7v+ (1 + 4a)w 2a28a11 u+ (6 − a)v + (4+ a)w 2a28a11
Transcribed Image Text:For the values of a for which the linear system 2x + ay + z = น x+2y+2az v x-3y+4z = พ has a unique solution, that solution is given by... Hint: Cramer's rule might be helpful here. ○ This system never has unique solutions. x = y = x = y = x = 8 y = x = (8+ 6a)u (3+ a)v + 2(a² - 2)w - 2a26a13 (2a-4)u+7v+ (1 - 4a)w 2a26a13 -5u+ (6+ a)v+ (4 − a)w 2a26a13 (8+ 6a)u (4a+3)v+ (2a2 - 2)w 2a28a11 (2a-4)u+7v + (1 - 4a)w 2a28a11 −5u+ (6+ a)v+ (4 − a)w 2a28a11 (6+8a)u+ (3+ a)v - 2(a² - 2)w 2a28a11 (a - 4)u+7v+ (1 + 4a)w 2a28a11 u+ (6 − a)v + (4+ a)w 2a28a11
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